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## Bladerunner1122 2 years ago Let R be the region in the first quadrant bounded by the graph y=3-√x the horizontal line y=1, and the y-axis as shown in the figure to the right.

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1. Bladerunner1122

http://goo.gl/AhgJX 1. Write but do not evaluate, an integral expression that gives the volume of the solid generated when R is rotated about the horizontal line y=-1. 2. Region R is the base of a solid. For each y, where 1≤y≤3, the cross section of the solid taken perpendicular to the y-axis is a rectangle whose height is half the length of its base. Write, but do not evaluate, an integral expression that gives the volume of the solid.

2. Bladerunner1122

? Anybody out there? xD

3. phi

|dw:1362167243909:dw|

4. phi

you need an expression for the radius of the discs, as a function of x

5. Bladerunner1122

??

6. Bladerunner1122

Isn't the volume $V=\pi \int\limits_{0}^{4}((-1-(3-√x))^2 -(-1-1)^2) dx$

7. phi

|dw:1362167608670:dw|

8. phi

yes, your expression looks good.

9. Bladerunner1122

Great! So what do I do for 2? I don't have any idea what to do for it.

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