Here's the question you clicked on:
Bladerunner1122
Let R be the region in the first quadrant bounded by the graph y=3-√x the horizontal line y=1, and the y-axis as shown in the figure to the right.
http://goo.gl/AhgJX 1. Write but do not evaluate, an integral expression that gives the volume of the solid generated when R is rotated about the horizontal line y=-1. 2. Region R is the base of a solid. For each y, where 1≤y≤3, the cross section of the solid taken perpendicular to the y-axis is a rectangle whose height is half the length of its base. Write, but do not evaluate, an integral expression that gives the volume of the solid.
? Anybody out there? xD
you need an expression for the radius of the discs, as a function of x
Isn't the volume \[V=\pi \int\limits_{0}^{4}((-1-(3-√x))^2 -(-1-1)^2) dx\]
yes, your expression looks good.
Great! So what do I do for 2? I don't have any idea what to do for it.