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Bladerunner1122 Group Title

Let R be the region bounded by the graphs of y=cos((pi x)/2) and y=x^2-(26/5)x+1. Find the area of R. http://goo.gl/vSltp

  • one year ago
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  1. Bladerunner1122 Group Title
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    I really just need confirmation that what I have is right. (hopefully it is anyway)

    • one year ago
  2. Bladerunner1122 Group Title
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    \[\int\limits_{0}^{5}(\cos(\pi x/2)-(x^2 - (26/5) x +1))dx=55/3 + 2/\pi = 18.97 \]

    • one year ago
  3. Bladerunner1122 Group Title
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    Does this make sense? I'm a little unsure.

    • one year ago
  4. Bladerunner1122 Group Title
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    @phi

    • one year ago
  5. phi Group Title
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    It is the correct setup, but I did not check your integration

    • one year ago
  6. Bladerunner1122 Group Title
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    As long as it's the correct setup then I'm glad for the reassurance. ;)

    • one year ago
  7. phi Group Title
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    top curve - lower curve gives a height height*dx gives an area integrate along x to get the total area.

    • one year ago
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