anonymous
  • anonymous
Let R be the region bounded by the graphs of y=cos((pi x)/2) and y=x^2-(26/5)x+1. Find the area of R. http://goo.gl/vSltp
Calculus1
jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
I really just need confirmation that what I have is right. (hopefully it is anyway)
anonymous
  • anonymous
\[\int\limits_{0}^{5}(\cos(\pi x/2)-(x^2 - (26/5) x +1))dx=55/3 + 2/\pi = 18.97 \]
anonymous
  • anonymous
Does this make sense? I'm a little unsure.

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anonymous
  • anonymous
@phi
phi
  • phi
It is the correct setup, but I did not check your integration
anonymous
  • anonymous
As long as it's the correct setup then I'm glad for the reassurance. ;)
phi
  • phi
top curve - lower curve gives a height height*dx gives an area integrate along x to get the total area.

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