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Bladerunner1122

  • one year ago

Let R be the region bounded by the graphs of y=cos((pi x)/2) and y=x^2-(26/5)x+1. Find the area of R. http://goo.gl/vSltp

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  1. Bladerunner1122
    • one year ago
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    I really just need confirmation that what I have is right. (hopefully it is anyway)

  2. Bladerunner1122
    • one year ago
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    \[\int\limits_{0}^{5}(\cos(\pi x/2)-(x^2 - (26/5) x +1))dx=55/3 + 2/\pi = 18.97 \]

  3. Bladerunner1122
    • one year ago
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    Does this make sense? I'm a little unsure.

  4. Bladerunner1122
    • one year ago
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    @phi

  5. phi
    • one year ago
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    It is the correct setup, but I did not check your integration

  6. Bladerunner1122
    • one year ago
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    As long as it's the correct setup then I'm glad for the reassurance. ;)

  7. phi
    • one year ago
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    top curve - lower curve gives a height height*dx gives an area integrate along x to get the total area.

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