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burhan101
 one year ago
Best ResponseYou've already chosen the best response.0dw:1362181886970:dw

tkhunny
 one year ago
Best ResponseYou've already chosen the best response.2\(\dfrac{\vec{a}\cdot \vec{b}}{\vec{a}\cdot \vec{b}} = \cos(\theta)\) where \(\theta\) is the angle you seek. This shoudl look very familiar.

zpupster
 one year ago
Best ResponseYou've already chosen the best response.0\[\(\dfrac{\vec{a}\cdot \vec{b}}{\vec{a}\cdot \vec{b}} = \cos(\theta)\) where \(\theta\)\] can you tell me how to read this, thanks

tkhunny
 one year ago
Best ResponseYou've already chosen the best response.2Is your browser not showing the symbols? It's the inner product divided by the product of the magnitudes. Taht is the cosine fo the angle.

zpupster
 one year ago
Best ResponseYou've already chosen the best response.0ok it is showing them now thanks
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