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.Sam.
 one year ago
Best ResponseYou've already chosen the best response.0Looks like implicit differentiation, do you know how to approach this problem?

YLynn
 one year ago
Best ResponseYou've already chosen the best response.0a bit. yes, it is implicit differentiation

.Sam.
 one year ago
Best ResponseYou've already chosen the best response.0Here, most of the work involve chain rule only

YLynn
 one year ago
Best ResponseYou've already chosen the best response.0differentiate each term d/dx ( ln x ) + d/dx (ln (y)

YLynn
 one year ago
Best ResponseYou've already chosen the best response.0how can you tell by looking at the equation

.Sam.
 one year ago
Best ResponseYou've already chosen the best response.0Differentiate (x+2)^2 you'll get 2(x+2) Differentiate 6(2y+3)^2 you'll get 12(2y+3)(2)(dy/dx) The 2 comes from chain rule, and dy/dx is differentiating with respect to x . Differentiate 3 is 0 Then you'll get \[2(x+2)12(2y+3)(2)\frac{dy}{dx}=0\] \[2(x+2)24(2y+3)\frac{dy}{dx}=0\] \[\frac{dy}{dx}=\frac{x+2}{24 y+36}\]

.Sam.
 one year ago
Best ResponseYou've already chosen the best response.0Because there's 2 terms together with a power, you'll have to use chain rule

.Sam.
 one year ago
Best ResponseYou've already chosen the best response.0Examples, 1) Differentiate 3(x+6)^2 dy/dx=6(x+6) 2) Differentiate 3(4x+2)^2 dy/dx=6(4x+2)(4) dy/dx=24(4x+2)

YLynn
 one year ago
Best ResponseYou've already chosen the best response.0ok. thanks for the examples. I understand those. For the question, the book gives an answer of: y'= 1/4 ?

Azteck
 one year ago
Best ResponseYou've already chosen the best response.0\[\huge D_{x}[(x+2)^26(2y+3)^2]=0\] \[\huge 2(x+2)24(\frac{dy}{dx})(2x+3)=0\] Divide both sides by 2. \[\huge (x+2)12(\frac{dy}{dx})(2x+3)=0\] Make dy/dx the subject. \[\huge \frac{dy}{dx}12(2x+3)=(x+2)\] \[\huge \frac{dy}{dx}=\frac{x+2}{12(2x+3)}\] At (1, 1) \[\huge \frac{dy}{dx}=\frac{1+2}{12[2(1)+3]}\] \[\huge \frac{dy}{dx}=\frac{3}{12(2+3)}\] \[\huge \frac{dy}{dx}=\frac{3}{12}\] \[\huge =\frac{1}{4}\]

Azteck
 one year ago
Best ResponseYou've already chosen the best response.0Use chain rule when differentiating in this situation.
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