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ketz

  • 3 years ago

Solve this quadratic equation: z2 + (2j - 3)z + (5 - j)=0

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  1. arjont
    • 3 years ago
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    is j here an imaginary number?

  2. arjont
    • 3 years ago
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    if j is just imaginary number then just use quadratic formula where you coefficients are a=1, b=(2j-3) and c=(5-j) most likely the j will cancel out once you take root

  3. harsimran_hs4
    • 3 years ago
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    let z = x +jy substitute in the above eq and tell me what you get (do separate the real and complex terms when you report your answer)

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