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  • hba

Stats help required

Mathematics
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  • hba
1 Attachment
\[mean = \frac{\sum fx}{\sum x}\]
ah, so it's just a weighted average.

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Other answers:

Solve the following for x: \[\frac{12(x-5)+40x+8(x+5)}{60}=10\]
  • hba
Whatt is the general formula @kropot72
\[\dfrac{\underbrace{x - 5 + x - 5 \cdots+ x-5}_{\rm 12 ~times} + \underbrace{x + x\cdots x + x}_{\rm 40 ~ times} + \underbrace{x + 5 +\cdots+ x+5}_{\rm 8 ~times}}{12 + 40 + 8}\]
  • hba
Thanks a lot but there would be some general form of this :/
  • hba
I wrote the general formula already.
  • hba
Shouldnt it be, \[\sum_{}^{}fx/\sum_{}^{}f\]
  • hba
Next.
1 Attachment
\[Arithmetic => \frac{x+y}{2} = 10.2\]
  • hba
What about geometric?
Geo mean formula: √(xy)
  • hba
Sqrt(x*y)
  • hba
Okay got it
\[√(xy) = 8.4\]
  • hba
Do i have to solve quad equations?
take square on both sides: xy = sqrt8.4 x = sqrt(8.4)/y
  • hba
I know that
Now substitute this in the first equation
  • hba
But it would be x=70.56/y
o_O
  • hba
Whut?
  • hba
sqrt(xy)=8.4 xy=70.56 x=70.56/y
Oh right.
Actually i'm doing two things at once. XD
  • hba
No worries c:,This thing is going into a quad equation :(
Go for it
  • hba
x=77.16,-56.76 and y=77.16,-56.76
  • hba
I feel like i have made a mistake :/
Let me check.
  • hba
Should i do it again?
x = 4.41, y = 15.99 x = 15.99, y = 4.41
  • hba
Lemme do it again,Stop playing with wolf :/
may i help?
  • hba
No thanks
ok do post your answer here
if you're completed with your soln
  • hba
I will
  • hba
Okay x=15.98,4.414 and y=4.414,15.98
great.
  • hba
Now next question, I am getting b=2,b=8 and a=8,a=2
1 Attachment
  • hba
So harmonic mean is 16/5=3.2
  • hba
Right @saifoo.khan ?
Never heard of harmonic mean. :s
  • hba
Okay lets call someone else for that case,What about the observation do you think they are right? Btw,A.M is opposite of H.M.
I cn help in HM
  • hba
And, H.M=N/(1/a1+1/a2+......1/an)
  • hba
@mathslover Do you think my answers are correct?
lemme check tht .. wait
  • hba
Okay
yep u r right
great work
  • hba
Thanks but now i want to ask, As i have two diff observations a=8,b=2 and a=2,b=8 and the HM is same so should i show this two times?
yes you have to mention that it will be same in both cases
  • hba
Okay now next question.
  • hba
Wait a sec
  • hba
1 Attachment
Namaz parhlo.
  • hba
Chalo okay namaz kai baad krtai hai.
  • hba
Han continue karlain @saifoo.khan
  • hba
@AravindG Can you help?
sorry I am a really busy ...
  • hba
I am really busy*
  • hba
@saifoo.khan I am waiting :/
  • hba
@hartnn Help pleaseeeeeeeeeeeeee
  • hba
@hartnn See the last attachment
same weighted average formula.
(700*8.5+800*7.5+500*8)/2000
\(\sum_{}^{}fx/\sum_{}^{}f\)
  • hba
I was thinking about using this but i am not getting why is sum of f=2000
sum of f = 700+800+500
  • hba
Okay thanks :)
  • hba
I am getting mean=7.85,Am i right? @mathslover
  • hba
7.975 https://www.google.co.in/search?q=(700*8.5%2B800*7.5%2B500*8)%2F2000&aq=f&oq=(700*8.5%2B800*7.5%2B500*8)%2F2000&aqs=chrome.0.57.460&sourceid=chrome&ie=UTF-8
  • hba
Close enough lol :P I am using a casio scientific calculator,I dont know why it rounded the answers :/
  • hba
Oh yeah i checked it again,Its 7.95 thanks. I have another question may i ask? @hartnn
yes
  • hba
Okay here we go :D
1 Attachment
you tried ?
  • hba
Wait wait dont answer i am trying
  • hba
\[\sum_{i=1}^{n}a_i=16.2\] Okay @hartnn Please explain

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