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burhan101
 2 years ago
Best ResponseYou've already chosen the best response.0dw:1362205701992:dw

arjont
 2 years ago
Best ResponseYou've already chosen the best response.0\[u*v=uv\cos\theta\]

arjont
 2 years ago
Best ResponseYou've already chosen the best response.0that would give you u dot v... but you need to find the components of each vector so that you can take the cross product. is it all thats given? is plotted on a accurate graph? maybe you can just read off the components from the graph

burhan101
 2 years ago
Best ResponseYou've already chosen the best response.0Thats all that's given !

arjont
 2 years ago
Best ResponseYou've already chosen the best response.0oh i see, you are basically given the hypotenuse of two triangles, i think you just take the components of each, where z component is 0 for both... but im not sure about your picture, since you can't tell the angles they with the horizontal

arjont
 2 years ago
Best ResponseYou've already chosen the best response.0*the angles they make with the horizontal

burhan101
 2 years ago
Best ResponseYou've already chosen the best response.0it has something to do with the right hand rule but im so confused with it !

harsimran_hs4
 2 years ago
Best ResponseYou've already chosen the best response.1magnitude of u cross v = uv sin(angle between them) as regards the direction is is always perpendicular to the plane containing these vectors

harsimran_hs4
 2 years ago
Best ResponseYou've already chosen the best response.1there are two perpendicular directions for a plane so: to determine which side follow this suppose you are to see the direction of a cross b keep your right hand`s base on a vector and curl to towards b and the direction in which the thumb points is the required direction

burhan101
 2 years ago
Best ResponseYou've already chosen the best response.0how do you know which one to curl it towards tho ?

harsimran_hs4
 2 years ago
Best ResponseYou've already chosen the best response.1a cross b you are to move from a to b
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