## anonymous 3 years ago Cross Product

1. anonymous

|dw:1362205701992:dw|

2. anonymous

$u*v=|u||v|\cos\theta$

3. anonymous

that would give you u dot v... but you need to find the components of each vector so that you can take the cross product. is it all thats given? is plotted on a accurate graph? maybe you can just read off the components from the graph

4. anonymous

Thats all that's given !

5. anonymous

oh i see, you are basically given the hypotenuse of two triangles, i think you just take the components of each, where z component is 0 for both... but im not sure about your picture, since you can't tell the angles they with the horizontal

6. anonymous

*the angles they make with the horizontal

7. anonymous

it has something to do with the right hand rule but im so confused with it !

8. harsimran_hs4

magnitude of u cross v = |u||v| sin(angle between them) as regards the direction is is always perpendicular to the plane containing these vectors

9. harsimran_hs4

there are two perpendicular directions for a plane so: to determine which side follow this suppose you are to see the direction of a cross b keep your right hand`s base on a vector and curl to towards b and the direction in which the thumb points is the required direction

10. anonymous

how do you know which one to curl it towards tho ?

11. harsimran_hs4

a cross b you are to move from a to b

12. harsimran_hs4

clear?

13. anonymous

yup, thanks !

14. harsimran_hs4

:)