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burhan101
 one year ago
Best ResponseYou've already chosen the best response.0dw:1362205701992:dw

arjont
 one year ago
Best ResponseYou've already chosen the best response.0\[u*v=uv\cos\theta\]

arjont
 one year ago
Best ResponseYou've already chosen the best response.0that would give you u dot v... but you need to find the components of each vector so that you can take the cross product. is it all thats given? is plotted on a accurate graph? maybe you can just read off the components from the graph

burhan101
 one year ago
Best ResponseYou've already chosen the best response.0Thats all that's given !

arjont
 one year ago
Best ResponseYou've already chosen the best response.0oh i see, you are basically given the hypotenuse of two triangles, i think you just take the components of each, where z component is 0 for both... but im not sure about your picture, since you can't tell the angles they with the horizontal

arjont
 one year ago
Best ResponseYou've already chosen the best response.0*the angles they make with the horizontal

burhan101
 one year ago
Best ResponseYou've already chosen the best response.0it has something to do with the right hand rule but im so confused with it !

harsimran_hs4
 one year ago
Best ResponseYou've already chosen the best response.1magnitude of u cross v = uv sin(angle between them) as regards the direction is is always perpendicular to the plane containing these vectors

harsimran_hs4
 one year ago
Best ResponseYou've already chosen the best response.1there are two perpendicular directions for a plane so: to determine which side follow this suppose you are to see the direction of a cross b keep your right hand`s base on a vector and curl to towards b and the direction in which the thumb points is the required direction

burhan101
 one year ago
Best ResponseYou've already chosen the best response.0how do you know which one to curl it towards tho ?

harsimran_hs4
 one year ago
Best ResponseYou've already chosen the best response.1a cross b you are to move from a to b
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