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that would give you u dot v... but you need to find the components of each vector so that you can take the cross product.
is it all thats given? is plotted on a accurate graph? maybe you can just read off the components from the graph
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Thats all that's given !
oh i see, you are basically given the hypotenuse of two triangles, i think you just take the components of each, where z component is 0 for both...
but im not sure about your picture, since you can't tell the angles they with the horizontal
*the angles they make with the horizontal
it has something to do with the right hand rule but im so confused with it !
u cross v = |u||v| sin(angle between them)
as regards the direction is is always perpendicular to the plane containing these vectors
there are two perpendicular directions for a plane so:
to determine which side follow this
suppose you are to see the direction of a cross b
keep your right hand`s base on a vector and curl to towards b and the direction in which the thumb points is the required direction
how do you know which one to curl it towards tho ?