anonymous
  • anonymous
Cross Product
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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anonymous
  • anonymous
|dw:1362205701992:dw|
anonymous
  • anonymous
\[u*v=|u||v|\cos\theta\]
anonymous
  • anonymous
that would give you u dot v... but you need to find the components of each vector so that you can take the cross product. is it all thats given? is plotted on a accurate graph? maybe you can just read off the components from the graph

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anonymous
  • anonymous
Thats all that's given !
anonymous
  • anonymous
oh i see, you are basically given the hypotenuse of two triangles, i think you just take the components of each, where z component is 0 for both... but im not sure about your picture, since you can't tell the angles they with the horizontal
anonymous
  • anonymous
*the angles they make with the horizontal
anonymous
  • anonymous
it has something to do with the right hand rule but im so confused with it !
harsimran_hs4
  • harsimran_hs4
magnitude of u cross v = |u||v| sin(angle between them) as regards the direction is is always perpendicular to the plane containing these vectors
harsimran_hs4
  • harsimran_hs4
there are two perpendicular directions for a plane so: to determine which side follow this suppose you are to see the direction of a cross b keep your right hand`s base on a vector and curl to towards b and the direction in which the thumb points is the required direction
anonymous
  • anonymous
how do you know which one to curl it towards tho ?
harsimran_hs4
  • harsimran_hs4
a cross b you are to move from a to b
harsimran_hs4
  • harsimran_hs4
clear?
anonymous
  • anonymous
yup, thanks !
harsimran_hs4
  • harsimran_hs4
:)

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