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|dw:1362205701992:dw|
\[u*v=|u||v|\cos\theta\]
that would give you u dot v... but you need to find the components of each vector so that you can take the cross product. is it all thats given? is plotted on a accurate graph? maybe you can just read off the components from the graph

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Other answers:

Thats all that's given !
oh i see, you are basically given the hypotenuse of two triangles, i think you just take the components of each, where z component is 0 for both... but im not sure about your picture, since you can't tell the angles they with the horizontal
*the angles they make with the horizontal
it has something to do with the right hand rule but im so confused with it !
magnitude of u cross v = |u||v| sin(angle between them) as regards the direction is is always perpendicular to the plane containing these vectors
there are two perpendicular directions for a plane so: to determine which side follow this suppose you are to see the direction of a cross b keep your right hand`s base on a vector and curl to towards b and the direction in which the thumb points is the required direction
how do you know which one to curl it towards tho ?
a cross b you are to move from a to b
clear?
yup, thanks !
:)

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