Quantcast

A community for students. Sign up today!

Here's the question you clicked on:

55 members online
  • 0 replying
  • 0 viewing

burhan101

  • one year ago

Cross Product

  • This Question is Closed
  1. burhan101
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    |dw:1362205701992:dw|

  2. arjont
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    \[u*v=|u||v|\cos\theta\]

  3. arjont
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    that would give you u dot v... but you need to find the components of each vector so that you can take the cross product. is it all thats given? is plotted on a accurate graph? maybe you can just read off the components from the graph

  4. burhan101
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    Thats all that's given !

  5. arjont
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    oh i see, you are basically given the hypotenuse of two triangles, i think you just take the components of each, where z component is 0 for both... but im not sure about your picture, since you can't tell the angles they with the horizontal

  6. arjont
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    *the angles they make with the horizontal

  7. burhan101
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    it has something to do with the right hand rule but im so confused with it !

  8. harsimran_hs4
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 1

    magnitude of u cross v = |u||v| sin(angle between them) as regards the direction is is always perpendicular to the plane containing these vectors

  9. harsimran_hs4
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 1

    there are two perpendicular directions for a plane so: to determine which side follow this suppose you are to see the direction of a cross b keep your right hand`s base on a vector and curl to towards b and the direction in which the thumb points is the required direction

  10. burhan101
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    how do you know which one to curl it towards tho ?

  11. harsimran_hs4
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 1

    a cross b you are to move from a to b

  12. harsimran_hs4
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 1

    clear?

  13. burhan101
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    yup, thanks !

  14. harsimran_hs4
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 1

    :)

  15. Not the answer you are looking for?
    Search for more explanations.

    Search OpenStudy
    • Attachments:

Ask your own question

Ask a Question
Find more explanations on OpenStudy

Your question is ready. Sign up for free to start getting answers.

spraguer (Moderator)
5 → View Detailed Profile

is replying to Can someone tell me what button the professor is hitting...

23

  • Teamwork 19 Teammate
  • Problem Solving 19 Hero
  • You have blocked this person.
  • ✔ You're a fan Checking fan status...

Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.

This is the testimonial you wrote.
You haven't written a testimonial for Owlfred.