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koli123able
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Find 'p' if 3x^2+2x+3p=0 has real & different roots.
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ANSWER = p<1/9
 one year ago
 one year ago
koli123able Group Title
Find 'p' if 3x^2+2x+3p=0 has real & different roots. . . ANSWER = p<1/9
 one year ago
 one year ago

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koli123able Group TitleBest ResponseYou've already chosen the best response.0
I have no idea on solving this question....
 one year ago

Xavier Group TitleBest ResponseYou've already chosen the best response.2
A quadratic has real and different roots if the descriminant is greater than zero: \[\Delta > 0\]
 one year ago

koli123able Group TitleBest ResponseYou've already chosen the best response.0
delta?? u mean discriminant?
 one year ago

koli123able Group TitleBest ResponseYou've already chosen the best response.0
so how D>0 ??
 one year ago

Xavier Group TitleBest ResponseYou've already chosen the best response.2
What do you mean? Set the discriminant to be greater than zero b^24ac > 0
 one year ago

koli123able Group TitleBest ResponseYou've already chosen the best response.0
I mean how is discriminant greater than zero can u explain?
 one year ago

harsimran_hs4 Group TitleBest ResponseYou've already chosen the best response.0
if d > 0 then there are real and different roots d = 0 real and equal roots d < 0 imaginary roots
 one year ago

agent0smith Group TitleBest ResponseYou've already chosen the best response.0
Real and different...? I'm guessing you mean real and distinct. But yes you can use the discriminant. When the discriminant is less than zero, it will have complex/imaginary roots, as the quadratic formula takes the square root of the discriminant ( http://www.purplemath.com/modules/quadform.htm ) \[3x^2+2x+3p=0 \]\[ax^2+bx+c = 0\] so here, a=3, b = 2 and c = 3p discriminant is \[b^24ac > 0 \]
 one year ago

koli123able Group TitleBest ResponseYou've already chosen the best response.0
If D>0 then sqrt(b^24ac) is a real number and roots are real and unequal
 one year ago

koli123able Group TitleBest ResponseYou've already chosen the best response.0
am I right?
 one year ago

harsimran_hs4 Group TitleBest ResponseYou've already chosen the best response.0
\[x = \frac{ b \pm \sqrt{b^2  4ac} }{ 2a }\] try putting different values of d and check out
 one year ago

harsimran_hs4 Group TitleBest ResponseYou've already chosen the best response.0
yes you are!!
 one year ago

koli123able Group TitleBest ResponseYou've already chosen the best response.0
as D>0 and D=b^24ac so, (2)^24*3*3p>0 436p>0 4>36p 1/9>0
 one year ago

koli123able Group TitleBest ResponseYou've already chosen the best response.0
is this ok?
 one year ago

Xavier Group TitleBest ResponseYou've already chosen the best response.2
You lost a p at the end
 one year ago

koli123able Group TitleBest ResponseYou've already chosen the best response.0
oh sorry I typed it in hurry
 one year ago
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