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krizzialeanne

  • one year ago

find the tension on each string if m=25 kg?

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  1. krizzialeanne
    • one year ago
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    |dw:1362211892089:dw|

  2. .Sam.
    • one year ago
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    Free body diagram, resolve the forces |dw:1362212492910:dw|

  3. .Sam.
    • one year ago
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    For both components, the sum of all forces is zero, since its not moving, For X component, \[T_2\cos(60)-T_1\cos(20)=0\] \[T_2=\frac{T_1\cos(20)}{\cos(60)}\] For Y component, \[T_1\sin(20)+T_2\sin(60)-25(9.81)=0\] \[T_1\sin(20)+(\frac{T_1\cos(20)}{\cos(60)})\sin(60)-25(9.81)=0\] Solve for Tension 1, just ask if anything you're not sure.

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