## anonymous 3 years ago find the tension on each string if m=25 kg?

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1. anonymous

|dw:1362211892089:dw|

2. .Sam.

Free body diagram, resolve the forces |dw:1362212492910:dw|

3. .Sam.

For both components, the sum of all forces is zero, since its not moving, For X component, $T_2\cos(60)-T_1\cos(20)=0$ $T_2=\frac{T_1\cos(20)}{\cos(60)}$ For Y component, $T_1\sin(20)+T_2\sin(60)-25(9.81)=0$ $T_1\sin(20)+(\frac{T_1\cos(20)}{\cos(60)})\sin(60)-25(9.81)=0$ Solve for Tension 1, just ask if anything you're not sure.