Quantcast

A community for students.

Here's the question you clicked on:

55 members online
  • 0 replying
  • 0 viewing

krizzialeanne

  • 2 years ago

find the tension on each string if m=25 kg?

  • This Question is Open
  1. krizzialeanne
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    |dw:1362211892089:dw|

  2. .Sam.
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 2

    Free body diagram, resolve the forces |dw:1362212492910:dw|

  3. .Sam.
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 2

    For both components, the sum of all forces is zero, since its not moving, For X component, \[T_2\cos(60)-T_1\cos(20)=0\] \[T_2=\frac{T_1\cos(20)}{\cos(60)}\] For Y component, \[T_1\sin(20)+T_2\sin(60)-25(9.81)=0\] \[T_1\sin(20)+(\frac{T_1\cos(20)}{\cos(60)})\sin(60)-25(9.81)=0\] Solve for Tension 1, just ask if anything you're not sure.

  4. Not the answer you are looking for?
    Search for more explanations.

    • Attachments:

Ask your own question

Sign Up
Find more explanations on OpenStudy

Your question is ready. Sign up for free to start getting answers.

spraguer (Moderator)
5 → View Detailed Profile

is replying to Can someone tell me what button the professor is hitting...

23

  • Teamwork 19 Teammate
  • Problem Solving 19 Hero
  • You have blocked this person.
  • ✔ You're a fan Checking fan status...

Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.

This is the testimonial you wrote.
You haven't written a testimonial for Owlfred.