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f(x)=2x^2−146x+c has 2 roots that are positive prime numbers. What is c?

Mathematics
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or roots to be positive D>0 i.e. b^2 - 4ac >0 D=b^2 - 4ac = (-146)^2 - (4*2*c)>0 =>21316 - 8c>0 =>8c<21316 => c<5329/2 is dis the ans??
use the sum of roots and product of roots formulae.
\[-\dfrac{146}{2} = \alpha + \beta\]and\[\dfrac{c}{a} = \alpha \beta\]where \(\alpha\), \(\beta\) are the required prime roots.

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Other answers:

Know any two prime numbers with sum \(73\)?
I meant\[\dfrac{-(-146)}{2} = \alpha + \beta\]
ya its 73
but 2 prime number tat makes 73??
Yeah, do you know any two such prime numbers with sum 73?
If one of this primes is odd, the second must be even, because \(\alpha +\beta=73\). But how many even primes do you know?
Start from the very first prime number and work your way through. That's a hint for you.
There is only one even prime number.
I stress on the word "first" in that statement.
And of course, when you subtract the even prime, you will get another prime.
@ParthKohli 17 - prime. 2 - even prime. If I subtract 17 - 2 = 15 - I will get not prime.
No, in this case you must!
This case is NOT having such a situation though :-)
...?
This question would have no answer if you would not get another prime number after subtracting 2.
Nobody guarantees you that this must have an answer.
Hey this is a problem of the present week's Brilliant Challenges... Shouldn't be discussed here actually... Between, Awesome site for maths lovers... https://brilliant.org/
really? :O
Yeah...
woah! :O
LOL!!! ^^

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