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rebecca1233

Find the perimeter of the following polygon.

  • one year ago
  • one year ago

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  1. rebecca1233
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    |dw:1362244727495:dw|

    • one year ago
  2. rebecca1233
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    26 29 36 39

    • one year ago
  3. rebecca1233
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    @sami-21

    • one year ago
  4. rebecca1233
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    @ZeHanz

    • one year ago
  5. rebecca1233
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    help quick please

    • one year ago
  6. rebecca1233
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    i thougth times but that isnt right

    • one year ago
  7. tcarroll010
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    Look at just the left half of the diagram for now. You have a right triangle and you have the measures of 2 sides, so you can use the Pythagorean Theorem: x^2 + 12^2 = 13^2 You can get x^2 from that and then get "x" Your perimeter will be easy from there.

    • one year ago
  8. rebecca1233
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    so i add 13+14+12+12

    • one year ago
  9. rebecca1233
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    ?

    • one year ago
  10. rebecca1233
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    i mean 13+13

    • one year ago
  11. rebecca1233
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    +12+12

    • one year ago
  12. tcarroll010
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    Well, first, you have to solve: x^2 + 12^2 = 13^2

    • one year ago
  13. rebecca1233
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    12*12?

    • one year ago
  14. rebecca1233
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    12+12 = 24

    • one year ago
  15. tcarroll010
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    Hint: subtract 12^2 from each side.

    • one year ago
  16. rebecca1233
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    ugh

    • one year ago
  17. rebecca1233
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    36 is the answer

    • one year ago
  18. rebecca1233
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    am i correct

    • one year ago
  19. tcarroll010
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    Don't worry, I'll help you: (x^2 + 12^2) - 12^2 = 13^2 - 12^2 x^2 + (12^2 - 12^2) = 13^2 - 12^2

    • one year ago
  20. tcarroll010
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    Yes, 36 is the answer! You got it!

    • one year ago
  21. tcarroll010
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    Good luck to you in all of your studies and thx for the recognition! @rebecca1233

    • one year ago
  22. rebecca1233
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    your welcome :)

    • one year ago
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