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rebecca1233

  • one year ago

Find the perimeter of the following polygon.

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  1. rebecca1233
    • one year ago
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    |dw:1362244727495:dw|

  2. rebecca1233
    • one year ago
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    26 29 36 39

  3. rebecca1233
    • one year ago
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    @sami-21

  4. rebecca1233
    • one year ago
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    @ZeHanz

  5. rebecca1233
    • one year ago
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    help quick please

  6. rebecca1233
    • one year ago
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    i thougth times but that isnt right

  7. tcarroll010
    • one year ago
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    Look at just the left half of the diagram for now. You have a right triangle and you have the measures of 2 sides, so you can use the Pythagorean Theorem: x^2 + 12^2 = 13^2 You can get x^2 from that and then get "x" Your perimeter will be easy from there.

  8. rebecca1233
    • one year ago
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    so i add 13+14+12+12

  9. rebecca1233
    • one year ago
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    ?

  10. rebecca1233
    • one year ago
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    i mean 13+13

  11. rebecca1233
    • one year ago
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    +12+12

  12. tcarroll010
    • one year ago
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    Well, first, you have to solve: x^2 + 12^2 = 13^2

  13. rebecca1233
    • one year ago
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    12*12?

  14. rebecca1233
    • one year ago
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    12+12 = 24

  15. tcarroll010
    • one year ago
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    Hint: subtract 12^2 from each side.

  16. rebecca1233
    • one year ago
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    ugh

  17. rebecca1233
    • one year ago
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    36 is the answer

  18. rebecca1233
    • one year ago
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    am i correct

  19. tcarroll010
    • one year ago
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    Don't worry, I'll help you: (x^2 + 12^2) - 12^2 = 13^2 - 12^2 x^2 + (12^2 - 12^2) = 13^2 - 12^2

  20. tcarroll010
    • one year ago
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    Yes, 36 is the answer! You got it!

  21. tcarroll010
    • one year ago
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    Good luck to you in all of your studies and thx for the recognition! @rebecca1233

  22. rebecca1233
    • one year ago
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    your welcome :)

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