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vortishBest ResponseYou've already chosen the best response.0
i do not think this can be factored i think it is a prime
 one year ago

vortishBest ResponseYou've already chosen the best response.0
i does not make sense 4 can not be factored in t o15
 one year ago

hartnnBest ResponseYou've already chosen the best response.1
how you could conclude that ? did you find out the value of determinant b^24ac ?
 one year ago

hartnnBest ResponseYou've already chosen the best response.1
actually you need to find 2 numbers with product 4*(15)=60 and sum 4
 one year ago

vortishBest ResponseYou've already chosen the best response.0
so what your saying i have to find a number that 60 will = 4
 one year ago

hartnnBest ResponseYou've already chosen the best response.1
2 numbers whose product is 60 and whose sum is 4 (here, one number is negative)
 one year ago

vortishBest ResponseYou've already chosen the best response.0
1086=60 10*6=60 106=4
 one year ago

hartnnBest ResponseYou've already chosen the best response.1
1086 ?? 10 and 6 are correct, so split +4u into 10u6u now try...
 one year ago

hartnnBest ResponseYou've already chosen the best response.1
huh ? no... 4u^2 +10u 6u 15 =0 factor out 2u from 1st 2 terms and 3 from last 2 terms, what u get ?
 one year ago

hartnnBest ResponseYou've already chosen the best response.1
?? (4u^2 +10u) + (6u 15) =0 2u (2u+5) 3 (2u+5) =0 got this ?
 one year ago

hartnnBest ResponseYou've already chosen the best response.1
now factor out 2u+5 from that
 one year ago

hartnnBest ResponseYou've already chosen the best response.1
2u+5 just disappeared :O :P (2u+5)(2u3) is your factored form :)
 one year ago

vortishBest ResponseYou've already chosen the best response.0
so you can only factor out one of the (2u+5) out of the expression
 one year ago

vortishBest ResponseYou've already chosen the best response.0
so the final answer would be (2u+5)(2u3)
 one year ago

hartnnBest ResponseYou've already chosen the best response.1
its like ab+ac = a(b+c) (2u+5)*2u + (2u+5)*(3) = (2u+5)(2u3) and yes.
 one year ago
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