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vortish

  • 3 years ago

factor the trinomial completely 4u^2+4u-15

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  1. hartnn
    • 3 years ago
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    tried this ?

  2. vortish
    • 3 years ago
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    i do not think this can be factored i think it is a prime

  3. vortish
    • 3 years ago
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    i does not make sense 4 can not be factored in t o15

  4. hartnn
    • 3 years ago
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    how you could conclude that ? did you find out the value of determinant b^2-4ac ?

  5. hartnn
    • 3 years ago
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    actually you need to find 2 numbers with product 4*(-15)=60 and sum 4

  6. hartnn
    • 3 years ago
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    4*(-15)=-60

  7. vortish
    • 3 years ago
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    so what your saying i have to find a number that -60 will = 4

  8. hartnn
    • 3 years ago
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    2 numbers whose product is -60 and whose sum is 4 (here, one number is negative)

  9. vortish
    • 3 years ago
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    -1086=-60 10*-6=-60 10-6=4

  10. hartnn
    • 3 years ago
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    -1086 ?? 10 and -6 are correct, so split +4u into 10u-6u now try...

  11. hartnn
    • 3 years ago
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    ohh, 10 & 6

  12. vortish
    • 3 years ago
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    (u+10)(u-6)

  13. hartnn
    • 3 years ago
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    huh ? no... 4u^2 +10u -6u -15 =0 factor out 2u from 1st 2 terms and -3 from last 2 terms, what u get ?

  14. vortish
    • 3 years ago
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    2u+4u -5

  15. hartnn
    • 3 years ago
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    ?? (4u^2 +10u) + (-6u -15) =0 2u (2u+5) -3 (2u+5) =0 got this ?

  16. vortish
    • 3 years ago
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    yes sir

  17. hartnn
    • 3 years ago
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    now factor out 2u+5 from that

  18. vortish
    • 3 years ago
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    (2u-3)=0

  19. hartnn
    • 3 years ago
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    2u+5 just disappeared :O :P (2u+5)(2u-3) is your factored form :)

  20. vortish
    • 3 years ago
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    so you can only factor out one of the (2u+5) out of the expression

  21. vortish
    • 3 years ago
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    so the final answer would be (2u+5)(2u-3)

  22. hartnn
    • 3 years ago
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    its like ab+ac = a(b+c) (2u+5)*2u + (2u+5)*(-3) = (2u+5)(2u-3) and yes.

  23. vortish
    • 3 years ago
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    ok thank you sir

  24. hartnn
    • 3 years ago
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    welcome ^_^

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