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vortish
 one year ago
Best ResponseYou've already chosen the best response.0i do not think this can be factored i think it is a prime

vortish
 one year ago
Best ResponseYou've already chosen the best response.0i does not make sense 4 can not be factored in t o15

hartnn
 one year ago
Best ResponseYou've already chosen the best response.1how you could conclude that ? did you find out the value of determinant b^24ac ?

hartnn
 one year ago
Best ResponseYou've already chosen the best response.1actually you need to find 2 numbers with product 4*(15)=60 and sum 4

vortish
 one year ago
Best ResponseYou've already chosen the best response.0so what your saying i have to find a number that 60 will = 4

hartnn
 one year ago
Best ResponseYou've already chosen the best response.12 numbers whose product is 60 and whose sum is 4 (here, one number is negative)

vortish
 one year ago
Best ResponseYou've already chosen the best response.01086=60 10*6=60 106=4

hartnn
 one year ago
Best ResponseYou've already chosen the best response.11086 ?? 10 and 6 are correct, so split +4u into 10u6u now try...

hartnn
 one year ago
Best ResponseYou've already chosen the best response.1huh ? no... 4u^2 +10u 6u 15 =0 factor out 2u from 1st 2 terms and 3 from last 2 terms, what u get ?

hartnn
 one year ago
Best ResponseYou've already chosen the best response.1?? (4u^2 +10u) + (6u 15) =0 2u (2u+5) 3 (2u+5) =0 got this ?

hartnn
 one year ago
Best ResponseYou've already chosen the best response.1now factor out 2u+5 from that

hartnn
 one year ago
Best ResponseYou've already chosen the best response.12u+5 just disappeared :O :P (2u+5)(2u3) is your factored form :)

vortish
 one year ago
Best ResponseYou've already chosen the best response.0so you can only factor out one of the (2u+5) out of the expression

vortish
 one year ago
Best ResponseYou've already chosen the best response.0so the final answer would be (2u+5)(2u3)

hartnn
 one year ago
Best ResponseYou've already chosen the best response.1its like ab+ac = a(b+c) (2u+5)*2u + (2u+5)*(3) = (2u+5)(2u3) and yes.
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