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factor the trinomial completely 4u^2+4u-15

Mathematics
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tried this ?
i do not think this can be factored i think it is a prime
i does not make sense 4 can not be factored in t o15

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Other answers:

how you could conclude that ? did you find out the value of determinant b^2-4ac ?
actually you need to find 2 numbers with product 4*(-15)=60 and sum 4
4*(-15)=-60
so what your saying i have to find a number that -60 will = 4
2 numbers whose product is -60 and whose sum is 4 (here, one number is negative)
-1086=-60 10*-6=-60 10-6=4
-1086 ?? 10 and -6 are correct, so split +4u into 10u-6u now try...
ohh, 10 & 6
(u+10)(u-6)
huh ? no... 4u^2 +10u -6u -15 =0 factor out 2u from 1st 2 terms and -3 from last 2 terms, what u get ?
2u+4u -5
?? (4u^2 +10u) + (-6u -15) =0 2u (2u+5) -3 (2u+5) =0 got this ?
yes sir
now factor out 2u+5 from that
(2u-3)=0
2u+5 just disappeared :O :P (2u+5)(2u-3) is your factored form :)
so you can only factor out one of the (2u+5) out of the expression
so the final answer would be (2u+5)(2u-3)
its like ab+ac = a(b+c) (2u+5)*2u + (2u+5)*(-3) = (2u+5)(2u-3) and yes.
ok thank you sir
welcome ^_^

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