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tried this ?

i do not think this can be factored i think it is a prime

i does not make sense 4 can not be factored in t o15

how you could conclude that ? did you find out the value of determinant b^2-4ac ?

actually you need to find 2 numbers with product 4*(-15)=60 and sum 4

4*(-15)=-60

so what your saying i have to find a number that -60 will = 4

2 numbers whose product is -60 and whose sum is 4
(here, one number is negative)

-1086=-60 10*-6=-60 10-6=4

-1086 ??
10 and -6 are correct,
so split +4u into 10u-6u
now try...

ohh, 10 & 6

(u+10)(u-6)

2u+4u -5

??
(4u^2 +10u) + (-6u -15) =0
2u (2u+5) -3 (2u+5) =0
got this ?

yes sir

now factor out 2u+5 from that

(2u-3)=0

2u+5 just disappeared :O :P
(2u+5)(2u-3) is your factored form :)

so you can only factor out one of the (2u+5) out of the expression

so the final answer would be (2u+5)(2u-3)

its like ab+ac = a(b+c)
(2u+5)*2u + (2u+5)*(-3) = (2u+5)(2u-3)
and yes.

ok thank you sir

welcome ^_^