Chad123 Group Title Solve: 3^2 - 2^2 / square root of 4 + square root of 49 using BIDMAS. Cheers one year ago one year ago

1. Mertsj Group Title

$\frac{3^3-2^2}{\sqrt{4}+\sqrt{49}}$

It is not written as a fraction

You have to use BIDMAS in the process

4. Mertsj Group Title

9-4/2+7= 9-2+7=7+7=14

Why can't it be 9-9=0 if addition and subtraction according to BIDMAS is of equal priority?

6. Mertsj Group Title

Because 4/2 means 4 divided by 2 and you must do the division before the addition and subtraction.

7. satellite73 Group Title

what the monkey is a bidmas?

8. Mertsj Group Title

brackets, indices, division multiplication, addition, subtraction

9. satellite73 Group Title

oooh sort of like "please excuse my senile aunt sally"

10. Mertsj Group Title

Precisely.

That wasn't my question. I said why did you do subtraction before addition?

If you did it the other way you would have got 9-9=0

13. waterineyes Group Title

$3^2 - 2^2 \div (\sqrt{4}) + \sqrt{49} \implies 9 - 4 \div 2 + 7$ According to BIDMAS rule, here you will divide first...

I know that part but why subtract and then do the division when it's supposed to be the opposite. Can't it be 9-9=0?

15. AravindG Group Title

what is I in BIDMAS ?

16. AravindG Group Title

Oh its above :P ....i got the same doubt as satellite ..we usually use the term BODMAS

17. hartnn Group Title

it can't be 9-9 because the order of operation (evaluation) is from left to right. so, 9-2 will be evaluated first, not 2+7