## anonymous 3 years ago Solve: 3^2 - 2^2 / square root of 4 + square root of 49 using BIDMAS. Cheers

1. Mertsj

$\frac{3^3-2^2}{\sqrt{4}+\sqrt{49}}$

2. anonymous

It is not written as a fraction

3. anonymous

You have to use BIDMAS in the process

4. Mertsj

9-4/2+7= 9-2+7=7+7=14

5. anonymous

Why can't it be 9-9=0 if addition and subtraction according to BIDMAS is of equal priority?

6. Mertsj

Because 4/2 means 4 divided by 2 and you must do the division before the addition and subtraction.

7. anonymous

what the monkey is a bidmas?

8. Mertsj

brackets, indices, division multiplication, addition, subtraction

9. anonymous

oooh sort of like "please excuse my senile aunt sally"

10. Mertsj

Precisely.

11. anonymous

That wasn't my question. I said why did you do subtraction before addition?

12. anonymous

If you did it the other way you would have got 9-9=0

13. anonymous

$3^2 - 2^2 \div (\sqrt{4}) + \sqrt{49} \implies 9 - 4 \div 2 + 7$ According to BIDMAS rule, here you will divide first...

14. anonymous

I know that part but why subtract and then do the division when it's supposed to be the opposite. Can't it be 9-9=0?

15. AravindG

what is I in BIDMAS ?

16. AravindG

Oh its above :P ....i got the same doubt as satellite ..we usually use the term BODMAS

17. hartnn

it can't be 9-9 because the order of operation (evaluation) is from left to right. so, 9-2 will be evaluated first, not 2+7