## e.cociuba 2 years ago *****Hardest math problem in the world?*** Here it is: (9^62773 + 2)^83721 Yes thats (9 to the 62773 power plus 2) to the 83721 power. Now heres the rest of the problem...after finding the Huge number i have to find its digital sum. if u dont know what that means just give me the answer to the problem. Metal to the person who gets this!! ( i just cant find a calculator that can do this!!!)

1. erdog82
2. erdog82

I think the digital root is the same as the digital sum

3. desigordon

the answer is 3

4. desigordon

i did the problem took 2 hours but i did it

5. erdog82

Yeah.. that is what my link says

6. e.cociuba

i didnt even post this 2 hrs ago :)

7. desigordon

huh i answered it you just gave him a link

8. erdog82

How did it take you two hours if this question was posted 7 minutes ago? @desigordon

9. desigordon

typo

10. desigordon

2 mins

11. desigordon

12. erdog82

Yeah, a link with the answer on it !!!! @desigordon

13. Koikkara

itz logarithms..... (9^62773 + 2)^83721= 83721 x log (9^62773 + 2) log (9^62773 + 2) = log (9^62773) +log ( 2) log (9^62773 + 2) = 62773 log (9) + log ( 2) log (9^62773 + 2) = 62773 (0.954242509) + ( 0.301029996) log (9^62773 + 2) = 59900.966 So: 83721 x log (9^62773 + 2)= (83721)(59900.966) 83721 x log (9^62773 + 2) =5.01496877 × 10^9 Digital sum is 5 + 0+ 1+4+9+6+8+7+7= 47 4+7=11 1+1=2

14. e.cociuba

I got 2. Too! @Koikkara

15. Mertsj

The log of the sum is NOT the sum of the logs!!!

16. desigordon

really so if i click the link and its blank the answer is trhere right

17. erdog82

Its 3 @Koikkara I think @e.cociuba

18. desigordon

its 3

19. erdog82

oh.. @desigordon It had it before

20. desigordon

i said the answer first so i win

21. e.cociuba

how is it 3??

22. erdog82

The digital root of (9^62773 + 2)^83721 is 3

23. desigordon

do you know logs

24. erdog82

The digital root of a number is the single digit that you get by adding all of the digits of the original number together. If the result of that is multiple digits, you add those digits together, repeating the process until you get a single digit. That digit is the digital root of the original number.

25. e.cociuba

k. yes i do

26. e.cociuba

k tnxs u guys!! Tht helped :)

27. desigordon

who gets medal

28. e.cociuba

I guess u do since u got the rite answer first!

29. desigordon

if you look at very top i said first answer

30. erdog82

Oh...

31. desigordon

32. erdog82

She, and your welcome

33. desigordon

i guess girls b4 guys so just give it to her she deserves it more than i do

34. erdog82

Thanks! ☺ @desigordon

35. desigordon

hey you guys mine helping me few a few problems

36. e.cociuba

Srry! @erdog82 my bad :) K then. Thts wat a man is all about @desigordon ! GBU :)

37. e.cociuba

Sure! Wtas up?

38. desigordon

how do you give medals

39. e.cociuba

U press 'Best Response' :)

40. desigordon

Solve the equation 3/2-1/x-4=-2/2x-8 . Use complete sentences to explain how you solved this equation.

41. desigordon

its a negative 2

42. desigordon

not positive

43. mathstudent55

@desigordon How do you know the digital root of (9^62773 + 2)^83721 is really 3? How did you calculate it?

44. e.cociuba

Ya! I'm not sure if the answer if really 3 @mathstudent55. Some help would be great!

45. mathstudent55

I have no idea what the answer is, but what I can tell you is that the link above www.thonky.com does not necessarily calculate it. It only looks at the digits you put in and ignores all other characters. If you enter a 2 in it, it returns 2. If you enter 23 it returns 5. So far, that's good because it's correct, but if you enter 2^3, it does not calculate that to be 8 and then return a value of 8. It will enter it as 23 (ignoring the ^ symbol) and will return a value of 5. Since the expression you are interested in has a sum and exponents, you are getting the root digit of the digits you are inputting and not of the enormous number the expression means.

46. TheOcean

the real answer is 2