*****Hardest math problem in the world?***
Here it is: (9^62773 + 2)^83721
Yes thats (9 to the 62773 power plus 2) to the 83721 power.
Now heres the rest of the problem...after finding the Huge number i have to find its digital sum. if u dont know what that means just give me the answer to the problem. Metal to the person who gets this!! ( i just cant find a calculator that can do this!!!)

- e.cociuba

- Stacey Warren - Expert brainly.com

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- schrodinger

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- anonymous

http://www.thonky.com/digital-root-calculator/

- anonymous

I think the digital root is the same as the digital sum

- anonymous

the answer is 3

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## More answers

- anonymous

i did the problem took 2 hours but i did it

- anonymous

Yeah.. that is what my link says

- e.cociuba

i didnt even post this 2 hrs ago :)

- anonymous

huh i answered it you just gave him a link

- anonymous

How did it take you two hours if this question was posted 7 minutes ago? @desigordon

- anonymous

typo

- anonymous

2 mins

- anonymous

my bad

- anonymous

Yeah, a link with the answer on it !!!! @desigordon

- Koikkara

itz logarithms.....
(9^62773 + 2)^83721= 83721 x log (9^62773 + 2)
log (9^62773 + 2) = log (9^62773) +log ( 2)
log (9^62773 + 2) = 62773 log (9) + log ( 2)
log (9^62773 + 2) = 62773 (0.954242509) + ( 0.301029996)
log (9^62773 + 2) = 59900.966
So:
83721 x log (9^62773 + 2)= (83721)(59900.966)
83721 x log (9^62773 + 2) =5.01496877 × 10^9
Digital sum is
5 + 0+ 1+4+9+6+8+7+7= 47
4+7=11
1+1=2

- e.cociuba

I got 2. Too! @Koikkara

- Mertsj

The log of the sum is NOT the sum of the logs!!!

- anonymous

really so if i click the link and its blank the answer is trhere right

- anonymous

Its 3 @Koikkara I think @e.cociuba

- anonymous

its 3

- anonymous

oh.. @desigordon It had it before

- anonymous

i said the answer first so i win

- e.cociuba

how is it 3??

- anonymous

The digital root of
(9^62773 + 2)^83721
is
3

- anonymous

do you know logs

- anonymous

The digital root of a number is the single digit that you get by adding all of the digits of the original number together. If the result of that is multiple digits, you add those digits together, repeating the process until you get a single digit. That digit is the digital root of the original number.

- e.cociuba

k. yes i do

- e.cociuba

k tnxs u guys!! Tht helped :)

- anonymous

who gets medal

- e.cociuba

I guess u do since u got the rite answer first!

- anonymous

if you look at very top i said first answer

- anonymous

Oh...

- anonymous

your right

- anonymous

She, and your welcome

- anonymous

i guess girls b4 guys so just give it to her she deserves it more than i do

- anonymous

Thanks! ☺ @desigordon

- anonymous

hey you guys mine helping me few a few problems

- e.cociuba

Srry! @erdog82 my bad :) K then. Thts wat a man is all about @desigordon ! GBU :)

- e.cociuba

Sure! Wtas up?

- anonymous

how do you give medals

- e.cociuba

U press 'Best Response' :)

- anonymous

Solve the equation 3/2-1/x-4=-2/2x-8 . Use complete sentences to explain how you solved this equation.

- anonymous

its a negative 2

- anonymous

not positive

- mathstudent55

@desigordon How do you know the digital root of (9^62773 + 2)^83721 is really 3? How did you calculate it?

- e.cociuba

Ya! I'm not sure if the answer if really 3 @mathstudent55. Some help would be great!

- mathstudent55

I have no idea what the answer is, but what I can tell you is that the link above www.thonky.com does not necessarily calculate it. It only looks at the digits you put in and ignores all other characters.
If you enter a 2 in it, it returns 2.
If you enter 23 it returns 5. So far, that's good because it's correct, but if you enter 2^3, it does not calculate that to be 8 and then return a value of 8. It will enter it as 23 (ignoring the ^ symbol) and will return a value of 5.
Since the expression you are interested in has a sum and exponents, you are getting the root digit of the digits you are inputting and not of the enormous number the expression means.

- anonymous

the real answer is 2

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