e.cociuba
  • e.cociuba
*****Hardest math problem in the world?*** Here it is: (9^62773 + 2)^83721 Yes thats (9 to the 62773 power plus 2) to the 83721 power. Now heres the rest of the problem...after finding the Huge number i have to find its digital sum. if u dont know what that means just give me the answer to the problem. Metal to the person who gets this!! ( i just cant find a calculator that can do this!!!)
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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chestercat
  • chestercat
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
http://www.thonky.com/digital-root-calculator/
anonymous
  • anonymous
I think the digital root is the same as the digital sum
anonymous
  • anonymous
the answer is 3

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More answers

anonymous
  • anonymous
i did the problem took 2 hours but i did it
anonymous
  • anonymous
Yeah.. that is what my link says
e.cociuba
  • e.cociuba
i didnt even post this 2 hrs ago :)
anonymous
  • anonymous
huh i answered it you just gave him a link
anonymous
  • anonymous
How did it take you two hours if this question was posted 7 minutes ago? @desigordon
anonymous
  • anonymous
typo
anonymous
  • anonymous
2 mins
anonymous
  • anonymous
my bad
anonymous
  • anonymous
Yeah, a link with the answer on it !!!! @desigordon
Koikkara
  • Koikkara
itz logarithms..... (9^62773 + 2)^83721= 83721 x log (9^62773 + 2) log (9^62773 + 2) = log (9^62773) +log ( 2) log (9^62773 + 2) = 62773 log (9) + log ( 2) log (9^62773 + 2) = 62773 (0.954242509) + ( 0.301029996) log (9^62773 + 2) = 59900.966 So: 83721 x log (9^62773 + 2)= (83721)(59900.966) 83721 x log (9^62773 + 2) =5.01496877 × 10^9 Digital sum is 5 + 0+ 1+4+9+6+8+7+7= 47 4+7=11 1+1=2
e.cociuba
  • e.cociuba
I got 2. Too! @Koikkara
Mertsj
  • Mertsj
The log of the sum is NOT the sum of the logs!!!
anonymous
  • anonymous
really so if i click the link and its blank the answer is trhere right
anonymous
  • anonymous
Its 3 @Koikkara I think @e.cociuba
anonymous
  • anonymous
its 3
anonymous
  • anonymous
oh.. @desigordon It had it before
anonymous
  • anonymous
i said the answer first so i win
e.cociuba
  • e.cociuba
how is it 3??
anonymous
  • anonymous
The digital root of (9^62773 + 2)^83721 is 3
anonymous
  • anonymous
do you know logs
anonymous
  • anonymous
The digital root of a number is the single digit that you get by adding all of the digits of the original number together. If the result of that is multiple digits, you add those digits together, repeating the process until you get a single digit. That digit is the digital root of the original number.
e.cociuba
  • e.cociuba
k. yes i do
e.cociuba
  • e.cociuba
k tnxs u guys!! Tht helped :)
anonymous
  • anonymous
who gets medal
e.cociuba
  • e.cociuba
I guess u do since u got the rite answer first!
anonymous
  • anonymous
if you look at very top i said first answer
anonymous
  • anonymous
Oh...
anonymous
  • anonymous
your right
anonymous
  • anonymous
She, and your welcome
anonymous
  • anonymous
i guess girls b4 guys so just give it to her she deserves it more than i do
anonymous
  • anonymous
Thanks! ☺ @desigordon
anonymous
  • anonymous
hey you guys mine helping me few a few problems
e.cociuba
  • e.cociuba
Srry! @erdog82 my bad :) K then. Thts wat a man is all about @desigordon ! GBU :)
e.cociuba
  • e.cociuba
Sure! Wtas up?
anonymous
  • anonymous
how do you give medals
e.cociuba
  • e.cociuba
U press 'Best Response' :)
anonymous
  • anonymous
Solve the equation 3/2-1/x-4=-2/2x-8 . Use complete sentences to explain how you solved this equation.
anonymous
  • anonymous
its a negative 2
anonymous
  • anonymous
not positive
mathstudent55
  • mathstudent55
@desigordon How do you know the digital root of (9^62773 + 2)^83721 is really 3? How did you calculate it?
e.cociuba
  • e.cociuba
Ya! I'm not sure if the answer if really 3 @mathstudent55. Some help would be great!
mathstudent55
  • mathstudent55
I have no idea what the answer is, but what I can tell you is that the link above www.thonky.com does not necessarily calculate it. It only looks at the digits you put in and ignores all other characters. If you enter a 2 in it, it returns 2. If you enter 23 it returns 5. So far, that's good because it's correct, but if you enter 2^3, it does not calculate that to be 8 and then return a value of 8. It will enter it as 23 (ignoring the ^ symbol) and will return a value of 5. Since the expression you are interested in has a sum and exponents, you are getting the root digit of the digits you are inputting and not of the enormous number the expression means.
anonymous
  • anonymous
the real answer is 2

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