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anonymous
 3 years ago
Can someone please help!!! I keep getting it wrong!!!
Find the extreme values of
f(xy)=3x^2+2y^2−4x−3 on the region described as x^2+y^2 is less than or equal to 4
anonymous
 3 years ago
Can someone please help!!! I keep getting it wrong!!! Find the extreme values of f(xy)=3x^2+2y^2−4x−3 on the region described as x^2+y^2 is less than or equal to 4

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harsimran_hs4
 3 years ago
Best ResponseYou've already chosen the best response.0hey have you heard of langranges multipliers or not?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0yea but i still got it wrong

harsimran_hs4
 3 years ago
Best ResponseYou've already chosen the best response.0ok so can you show the working ...

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0yea this is what i did: f_x=6x4<=4 6x<=8 x<=4/3 f_y=4y<=4 f_y<=1 fxx=6 fyy=4

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0and then i got stuck so i assumed the max was 6 and min was 1

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0but then i tried plugging in the values to the orginal equation and the number seemed wrong so idk what to do

harsimran_hs4
 3 years ago
Best ResponseYou've already chosen the best response.0firstly tell me that you want to proceed using concept of maxima minima using partial derivatives of langranges multipliers

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0is there an easier way

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0im good with anything

harsimran_hs4
 3 years ago
Best ResponseYou've already chosen the best response.0well perhaps i don`t think so because it`s gone in 2 dimension so lets do it by langranges multipliers 1. tell me what is gradient of f(x,y) ?

harsimran_hs4
 3 years ago
Best ResponseYou've already chosen the best response.0so that is (6x 4)i + (4y)j tell me the same for the boundary x^2 + y^2 = 4 also?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0im not sure im confused

harsimran_hs4
 3 years ago
Best ResponseYou've already chosen the best response.0yes that is fine (2x)i + (2y)j so for extreme values to occur the gradient of the function and that of the boundary must be proportional so (6x 4)i + (4y)j = c((2x)i + (2y)j) now compare the i and j components and find the value of x and y in terms of c and tell me?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0sry im not exactly sure what you mean

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0and whered the c come from

harsimran_hs4
 3 years ago
Best ResponseYou've already chosen the best response.06x  4 = 2cx and 4y = 2cy c is the proportionality constant better say the extreme values occurs when the gradient of two is antiparallel or proportional

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0im sry im not sure what to do now

harsimran_hs4
 3 years ago
Best ResponseYou've already chosen the best response.0x = 4/(6  2c) and c = 2 from second equation so x = 2 not the boundary x^2 + y^2 = 4 putting x = 2 and finding out value of y which come out to be 0 so (2, 0) is the point of extreme value

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0so 2 is the max and 0 is the min

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0or do we plus in 2 into the equatio and thats hte max and 0 is the min

harsimran_hs4
 3 years ago
Best ResponseYou've already chosen the best response.0no the point (2, 0) will result in the extreme value of the function put x = 2 and y = 0 to yield the extreme value

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0but wouldnt that result in just one value and not max and min

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0yr supposed to find absolute max and min and i got the answer ot be 1 which is wrong

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0@harsimran_hs4 did you get 1 as well

harsimran_hs4
 3 years ago
Best ResponseYou've already chosen the best response.0yes perhaps then we screwed up with the calculation part can you tell me the answers if you have them with you?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0the answers arent given :(

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0its an online hw thing

harsimran_hs4
 3 years ago
Best ResponseYou've already chosen the best response.0ok then why did you say it`s wrong?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0because i plugged t in and it said it was wrong

harsimran_hs4
 3 years ago
Best ResponseYou've already chosen the best response.0ok let me figure out then and i`ll get back to you

harsimran_hs4
 3 years ago
Best ResponseYou've already chosen the best response.0can you plug in 3 and check if thats minimum value?

harsimran_hs4
 3 years ago
Best ResponseYou've already chosen the best response.0do you get ve points if you put in a wrong answer if no then check out if 9 is maximum or not

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0i only have one more try left to find out what the max and min is

harsimran_hs4
 3 years ago
Best ResponseYou've already chosen the best response.0you need to plug in both the values simultaneously or not?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0yea but i can still get partial pints

harsimran_hs4
 3 years ago
Best ResponseYou've already chosen the best response.0http://www.math.uri.edu/~bkaskosz/flashmo/graph3d/ check this this will give some insight to the problem but do link someone else also to this problem and figure out... i`ll try to get to some sure answer and then reply
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