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hartnn
 2 years ago
Best ResponseYou've already chosen the best response.0do we "have to" integrate by parts ? because a simple substitution will make this integral lot easier to solve

shaqadry
 2 years ago
Best ResponseYou've already chosen the best response.0yes the question requires it to be solve by parts.

hartnn
 2 years ago
Best ResponseYou've already chosen the best response.0so, do you know integration by parts ? have u tried this ?

SithsAndGiggles
 2 years ago
Best ResponseYou've already chosen the best response.0Going with the sub first would probably help make the bypartsintegration less messy.

shaqadry
 2 years ago
Best ResponseYou've already chosen the best response.0i've tried it before but now i forgot from where i should start :( @hartnn

hartnn
 2 years ago
Best ResponseYou've already chosen the best response.0do you know the formula for integrating by parts ? (actually there are 2 equivalent formulas, and i wanna know which one do u use)

shaqadry
 2 years ago
Best ResponseYou've already chosen the best response.0integrate udv = uv  integrate vdu

hartnn
 2 years ago
Best ResponseYou've already chosen the best response.0so whats your choice of u and dv ?

shaqadry
 2 years ago
Best ResponseYou've already chosen the best response.0idk i tried both i i ciuld find the answers T.T

shaqadry
 2 years ago
Best ResponseYou've already chosen the best response.0yes thank you so much @sami21

.Sam.
 2 years ago
Best ResponseYou've already chosen the best response.1@sami21 From \[\frac{x(1+2x)^6}{12}+\frac{1}{12}\int\limits(1+2x)^6 dx \\ \\ \frac{x(1+2x)^6}{12}+\frac{1}{12}(\frac{(1+2x)^7}{7(2)})+c \\ \\ \frac{x(1+2x)^6}{12}+\frac{(1+2x)^7}{168}+c\]

sami21
 2 years ago
Best ResponseYou've already chosen the best response.1i missed the 2 ! thnx @.Sam. for clarification.

shaqadry
 2 years ago
Best ResponseYou've already chosen the best response.0yes i got it thank you :)
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