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hartnn
 one year ago
Best ResponseYou've already chosen the best response.0do we "have to" integrate by parts ? because a simple substitution will make this integral lot easier to solve

shaqadry
 one year ago
Best ResponseYou've already chosen the best response.0yes the question requires it to be solve by parts.

hartnn
 one year ago
Best ResponseYou've already chosen the best response.0so, do you know integration by parts ? have u tried this ?

SithsAndGiggles
 one year ago
Best ResponseYou've already chosen the best response.0Going with the sub first would probably help make the bypartsintegration less messy.

shaqadry
 one year ago
Best ResponseYou've already chosen the best response.0i've tried it before but now i forgot from where i should start :( @hartnn

hartnn
 one year ago
Best ResponseYou've already chosen the best response.0do you know the formula for integrating by parts ? (actually there are 2 equivalent formulas, and i wanna know which one do u use)

shaqadry
 one year ago
Best ResponseYou've already chosen the best response.0integrate udv = uv  integrate vdu

hartnn
 one year ago
Best ResponseYou've already chosen the best response.0so whats your choice of u and dv ?

shaqadry
 one year ago
Best ResponseYou've already chosen the best response.0idk i tried both i i ciuld find the answers T.T

shaqadry
 one year ago
Best ResponseYou've already chosen the best response.0yes thank you so much @sami21

.Sam.
 one year ago
Best ResponseYou've already chosen the best response.1@sami21 From \[\frac{x(1+2x)^6}{12}+\frac{1}{12}\int\limits(1+2x)^6 dx \\ \\ \frac{x(1+2x)^6}{12}+\frac{1}{12}(\frac{(1+2x)^7}{7(2)})+c \\ \\ \frac{x(1+2x)^6}{12}+\frac{(1+2x)^7}{168}+c\]

sami21
 one year ago
Best ResponseYou've already chosen the best response.1i missed the 2 ! thnx @.Sam. for clarification.

shaqadry
 one year ago
Best ResponseYou've already chosen the best response.0yes i got it thank you :)
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