A community for students.
Here's the question you clicked on:
 0 viewing
ketz
 3 years ago
Solve: z4 + 2z3 + 5z2 + 8z + 4 = 0
It's urgent...
ketz
 3 years ago
Solve: z4 + 2z3 + 5z2 + 8z + 4 = 0 It's urgent...

This Question is Closed

shubhamsrg
 3 years ago
Best ResponseYou've already chosen the best response.0www.wolframalpha.com

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Using rational root theorem u can realize that z=1 is a solution...

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0so u can factor out z+1\[ z^4 + 2z^3 + 5z^2 + 8z + 4=z^4+z^3+z^3+z^2+4z^2+4z+4z+4\]\[=(z+1)(z^3+z^2+4z+4)\]

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0now for the cubic part ..easily u can see that z=1 is a solution for that so u can factor out z+1 from that too\[(z+1)(z^3+z^2+4z+4)=(z+1)(z^2(z+1)+4(z+1))=(z+1)^2(z^2+4)\]we're done

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0\[z^4+2z^3+5z^2+8z+4=(z+1)^2(z^2+4)\]

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0\[z=1, \pm2i\]i think u want real root so \[z=1\]
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.