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sami21Best ResponseYou've already chosen the best response.2
try substitution t=x^2 dt=2xdx 1/2dt=xdx
 one year ago

shaqadryBest ResponseYou've already chosen the best response.0
can i do partial fraction method?
 one year ago

agent0smithBest ResponseYou've already chosen the best response.0
\[\int\limits \frac{ 2 }{ x (x^2+1)^2} dx\] Hmm. Use partial fractions?
 one year ago

sami21Best ResponseYou've already chosen the best response.2
yes you can use partial fraction . i guess fractions will be easy with linear terms so use t=x^2 dt=2xdx \[\Large \int\limits \frac{dt}{t(t+1)^2}\] now use partial fractions .
 one year ago

sami21Best ResponseYou've already chosen the best response.2
no we can write the original integral as \[\Large \int\limits \frac{2xdx}{x^2(x^2+1)}\] so let t=x^2 dt=2xdx
 one year ago

deena123Best ResponseYou've already chosen the best response.0
\[2\left( \frac{ 1 }{ 2(x^2+1) }\frac{ 1 }{ 2 }\log(x^2+1)+\log x \right)\]
 one year ago

shaqadryBest ResponseYou've already chosen the best response.0
@sami21 i dont understand
 one year ago

mathsmindBest ResponseYou've already chosen the best response.0
you can use partial fraction, this is because if the power of the denominator is greater than the power of the numerator that would be an alternative method...
 one year ago

mathsmindBest ResponseYou've already chosen the best response.0
but for me personal i prefer the first method present by sami....
 one year ago

mathsmindBest ResponseYou've already chosen the best response.0
did u solve the problem?
 one year ago
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