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what's your question?
I have worked over this problem
AM=4 x+3+2+0+8+y+3+4/8=4 x+y+20=32 x+y=12
going good so far
Now what i see is that 4 is given as the mode so x and y should also be 4 but that is not the case :/
Looks like the question is wrong
why x AND y ?? any one of them can be 4
No but as its the mode so it should be the most recurring.....
I mean to say that 3 occurs 2 times and it is not the mode.So 4 should occur 3 times to be the mode
And if 3 is 2 times 4 is 2 times and then 8 would be 2 times,We have 3 modes here
yes so what? we can select mode as any 1 of the 3, and we select here 4
Okay got it,What should my step be now?
What should i do after getting an eqn?
take any one of 'x' or 'y' as 4
Okay got it thanks a lot,but what should i state
Why am i taking x or y as 4?
I need to do some reasoning?
because mode =4 if none of x or y is 4, then mode cannot be 4
Got it bro thanks :D