## hba 2 years ago Stats help needed

1. chihiroasleaf

2. hba

Good Question @chihiroasleaf

3. hba

I have worked over this problem

4. uri

Faizan :o

5. hba

AM=4 x+3+2+0+8+y+3+4/8=4 x+y+20=32 x+y=12

6. hartnn

going good so far

7. hba

Now what i see is that 4 is given as the mode so x and y should also be 4 but that is not the case :/

8. hba

Looks like the question is wrong

9. hartnn

why x AND y ?? any one of them can be 4

10. hba

No but as its the mode so it should be the most recurring.....

11. hba

I mean to say that 3 occurs 2 times and it is not the mode.So 4 should occur 3 times to be the mode

12. hba

And if 3 is 2 times 4 is 2 times and then 8 would be 2 times,We have 3 modes here

13. hartnn

yes so what? we can select mode as any 1 of the 3, and we select here 4

14. hba

Okay got it,What should my step be now?

15. hba

What should i do after getting an eqn?

16. hartnn

take any one of 'x' or 'y' as 4

17. hba

Okay got it thanks a lot,but what should i state

18. hba

Why am i taking x or y as 4?

19. hba

I need to do some reasoning?

20. hartnn

because mode =4 if none of x or y is 4, then mode cannot be 4

21. hba

Got it bro thanks :D

22. hartnn

welcome :)