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chihiroasleaf
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what's your question?

hba
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Good Question @chihiroasleaf

hba
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I have worked over this problem

uri
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Faizan :o

hba
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AM=4
x+3+2+0+8+y+3+4/8=4
x+y+20=32
x+y=12

hartnn
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going good so far

hba
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Now what i see is that 4 is given as the mode so x and y should also be 4 but that is not the case :/

hba
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Looks like the question is wrong

hartnn
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why x AND y ??
any one of them can be 4

hba
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No but as its the mode so it should be the most recurring.....

hba
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I mean to say that 3 occurs 2 times and it is not the mode.So 4 should occur 3 times to be the mode

hba
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And if 3 is 2 times 4 is 2 times and then 8 would be 2 times,We have 3 modes here

hartnn
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yes so what? we can select mode as any 1 of the 3, and we select here 4

hba
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Okay got it,What should my step be now?

hba
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What should i do after getting an eqn?

hartnn
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take any one of 'x' or 'y' as 4

hba
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Okay got it thanks a lot,but what should i state

hba
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Why am i taking x or y as 4?

hba
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I need to do some reasoning?

hartnn
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because mode =4
if none of x or y is 4, then mode cannot be 4

hba
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Got it bro thanks :D

hartnn
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welcome :)