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chihiroasleaf Group TitleBest ResponseYou've already chosen the best response.0
what's your question?
 one year ago

hba Group TitleBest ResponseYou've already chosen the best response.0
Good Question @chihiroasleaf
 one year ago

hba Group TitleBest ResponseYou've already chosen the best response.0
I have worked over this problem
 one year ago

hba Group TitleBest ResponseYou've already chosen the best response.0
AM=4 x+3+2+0+8+y+3+4/8=4 x+y+20=32 x+y=12
 one year ago

hartnn Group TitleBest ResponseYou've already chosen the best response.1
going good so far
 one year ago

hba Group TitleBest ResponseYou've already chosen the best response.0
Now what i see is that 4 is given as the mode so x and y should also be 4 but that is not the case :/
 one year ago

hba Group TitleBest ResponseYou've already chosen the best response.0
Looks like the question is wrong
 one year ago

hartnn Group TitleBest ResponseYou've already chosen the best response.1
why x AND y ?? any one of them can be 4
 one year ago

hba Group TitleBest ResponseYou've already chosen the best response.0
No but as its the mode so it should be the most recurring.....
 one year ago

hba Group TitleBest ResponseYou've already chosen the best response.0
I mean to say that 3 occurs 2 times and it is not the mode.So 4 should occur 3 times to be the mode
 one year ago

hba Group TitleBest ResponseYou've already chosen the best response.0
And if 3 is 2 times 4 is 2 times and then 8 would be 2 times,We have 3 modes here
 one year ago

hartnn Group TitleBest ResponseYou've already chosen the best response.1
yes so what? we can select mode as any 1 of the 3, and we select here 4
 one year ago

hba Group TitleBest ResponseYou've already chosen the best response.0
Okay got it,What should my step be now?
 one year ago

hba Group TitleBest ResponseYou've already chosen the best response.0
What should i do after getting an eqn?
 one year ago

hartnn Group TitleBest ResponseYou've already chosen the best response.1
take any one of 'x' or 'y' as 4
 one year ago

hba Group TitleBest ResponseYou've already chosen the best response.0
Okay got it thanks a lot,but what should i state
 one year ago

hba Group TitleBest ResponseYou've already chosen the best response.0
Why am i taking x or y as 4?
 one year ago

hba Group TitleBest ResponseYou've already chosen the best response.0
I need to do some reasoning?
 one year ago

hartnn Group TitleBest ResponseYou've already chosen the best response.1
because mode =4 if none of x or y is 4, then mode cannot be 4
 one year ago

hba Group TitleBest ResponseYou've already chosen the best response.0
Got it bro thanks :D
 one year ago
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