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hartnn Group TitleBest ResponseYou've already chosen the best response.2
do you know how to generally factor a quadratic ?
 one year ago

Christos Group TitleBest ResponseYou've already chosen the best response.0
I know some methods but I guess I miss this one
 one year ago

hartnn Group TitleBest ResponseYou've already chosen the best response.2
for \(ax^2+bx+c\), you need to find 2 numbers with sum = b and product = ac so, for your question, you need to find 2 numbers with sum =37 and product = 20*15 = 300
 one year ago

Christos Group TitleBest ResponseYou've already chosen the best response.0
I see now :)
 one year ago

hartnn Group TitleBest ResponseYou've already chosen the best response.2
so which 2 numbers u get ? then split 37x accordingly...
 one year ago

Christos Group TitleBest ResponseYou've already chosen the best response.0
I got 20 and 15 what now?
 one year ago

hartnn Group TitleBest ResponseYou've already chosen the best response.2
good! split 37x as 20x15x so, you have \(15x^215x20x+20\) there's a common factor in 1st 2 terms and a common factor in last 2 terms, can you proceed ?
 one year ago

hartnn Group TitleBest ResponseYou've already chosen the best response.2
oh wait, 20 and 15 are incorrect :P
 one year ago

hartnn Group TitleBest ResponseYou've already chosen the best response.2
try another pair ?
 one year ago

Christos Group TitleBest ResponseYou've already chosen the best response.0
12 25 ?
 one year ago

hartnn Group TitleBest ResponseYou've already chosen the best response.2
bingo! split 37x as 25x12x so, you have \(15x^2−25x−12x+20\) there's a common factor in 1st 2 terms and a common factor in last 2 terms, can you proceed ?
 one year ago

Christos Group TitleBest ResponseYou've already chosen the best response.0
x(x1525)4(3x + 5)
 one year ago

hartnn Group TitleBest ResponseYou've already chosen the best response.2
from first 2 terms factor out 5x
 one year ago

Christos Group TitleBest ResponseYou've already chosen the best response.0
5x(3x  5)  4(3x + 20)
 one year ago

hartnn Group TitleBest ResponseYou've already chosen the best response.2
12x+20 = 4 (3x+.....?)
 one year ago

Christos Group TitleBest ResponseYou've already chosen the best response.0
its 5 sorry
 one year ago

hartnn Group TitleBest ResponseYou've already chosen the best response.2
so, now factor 3x5 from that
 one year ago

Christos Group TitleBest ResponseYou've already chosen the best response.0
What do you mean? I dont understand :SS
 one year ago

hartnn Group TitleBest ResponseYou've already chosen the best response.2
5x (3x5) 4(3x5) factor out 3x5 (3x5)(5x4) i meant this, and you're done
 one year ago

LadyKatsaTheGraceling Group TitleBest ResponseYou've already chosen the best response.0
Bonjour! Comment allez vous?
 one year ago

hartnn Group TitleBest ResponseYou've already chosen the best response.2
i am fine, do u need any help ? with what ?
 one year ago

LadyKatsaTheGraceling Group TitleBest ResponseYou've already chosen the best response.0
You are very good at teaching people
 one year ago

hartnn Group TitleBest ResponseYou've already chosen the best response.2
oh, thank you very much :) :D
 one year ago

some_someone Group TitleBest ResponseYou've already chosen the best response.0
\[15x^2  37x + 20 \] \[(3 x5) (5 x4)\]
 one year ago
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