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|dw:1362323572542:dw|

@UnkleRhaukus
My first time doing a circuit problem
Let's see how much I know....

should I "add" \(C_1 \;\text{and}\; C_2\) first?

@.Sam.

|dw:1362324461114:dw|
these are in parallel...no they're in series correct?

|dw:1362324513695:dw|
is my charge distribution correct so far?

does that mean \(Q_1 \ne Q_2\)

This is physics

I'll move my question

|dw:1362325488170:dw|
Series

yes

so \(C_1=C_2\)

I don't think you can say that they're equal

are the charges equal? \[Q_1=Q_2\]
|dw:1362325598105:dw|

or should they be opposite in sign?

The sign is correct

|dw:1362325984158:dw|
The potential is probably different between \[C_1 & C_2\]

I mean it makes sense mathematically, I'm trying to conceptually understand it

Let's see....

are \[\frac 1 C+C_3=\text{to some other C}\] since they're within the same enclosed circuit

oh I see...you're just giving me a general statement...sorry :S

so yes, for "all the capacitors in series" the Voltages add up

|dw:1362328282074:dw|

That's series, there's no obvious branching lines.

oops I forgot something

\[\frac 1 {C_{Total}}=\frac{1}{\frac{C_1C_2}{C_2+C_1}+C_3}+\frac{1}{C_4}\]

did we just achieve the goal of this problem? Is that it?

why do you have C_Total instead of 1/C_total?

The final answer should be\[\frac{1}{C_{Total}}=\frac{1}{\frac{C_1 C_2}{C_1+C_2}+C_3}+\frac{1}{C_4}\]
But then, I usually work out the numbers first then substitute into another equation that way is not so confusing :)

oh I see....

one more question
|dw:1362329932879:dw|
would this be a parallel series?

You need to know where's the power coming from..

|dw:1362330036313:dw|

that's the power right?

Series, you can ignore that middle line|dw:1362330096032:dw|

can you draw capacitors in parallel for me

oh so does parallel mean parallel to the power supply?

I mean
C_T and C_4....typo :S

Parallel capacitors is \[V=V_1=V_2\]

oh interesting
Let's see
\[V=\frac Q C\]
\[\frac Q C=\frac{Q_1}{C_1}=\frac{Q_2}{C_2}\]

Q's the same again?

That's in parallel, you have to remember.

Series= Charges equal
Parallel= Voltage equal

Yes! Makes sense :)

hahaha, welcome :)