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happykiddo

  • 3 years ago

please show me how to factor::: 2x^2-19x+24

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  1. happykiddo
    • 3 years ago
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    i know the answer is (x-8) (2x-3).........but how exactly would i get that?

  2. ajprincess
    • 3 years ago
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    2x^2-19x+24 First multiply the coefficient of x^2 and the constant. That is, the coefficient of x^2 here is 2 nd constant is 24. 2*24=48 Then find two factors of 48 such that their sum is -19 and product is 48. That is if the factors are a and b a+b=-19 a*b=48

  3. happykiddo
    • 3 years ago
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    yeah but 24 and 2 dont add up to -19 or any of the other multiples i can think of for 48

  4. ajprincess
    • 3 years ago
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    I think the expression u have given shoul be 2x^2-11x+48 and nt 2x^2-19x+48. plzz chck

  5. happykiddo
    • 3 years ago
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    no its still 2x^2-19x+24

  6. ajprincess
    • 3 years ago
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    ya u r right. Am sorry. Let me list out the factors of 48 1,2,3,4,6,8,12,16,24,48,-1,-2,-3,-4,-6,-8,-12,-16,-24,-48. Nw chck if u can find those numbers

  7. ajprincess
    • 3 years ago
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    hw abt -3 and -16

  8. happykiddo
    • 3 years ago
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    so the answer should be (2x-3) (x-16)..........not what the book gives me which is (x-8) (2x-3)

  9. ajprincess
    • 3 years ago
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    2x^2-19x+24 =2x^2-16x-3x+24 =2x(x-8)-3(x-8)

  10. ajprincess
    • 3 years ago
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    After finding the numbers u have to split only the mid term using thm. Gettng t? @happykiddo

  11. happykiddo
    • 3 years ago
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    oh i see where your going with this THANK YOU :D

  12. happykiddo
    • 3 years ago
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    this really helped.

  13. ajprincess
    • 3 years ago
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    Glad to hear that nd welcome:)

  14. happykiddo
    • 3 years ago
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    yay i just got two more problems right. i dont think i'll be needing more help : )

  15. ajprincess
    • 3 years ago
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    Congrats for gettng ur problems rght:)

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