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happykiddo
 2 years ago
please show me how to factor:::
2x^219x+24
happykiddo
 2 years ago
please show me how to factor::: 2x^219x+24

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happykiddo
 2 years ago
Best ResponseYou've already chosen the best response.0i know the answer is (x8) (2x3).........but how exactly would i get that?

ajprincess
 2 years ago
Best ResponseYou've already chosen the best response.12x^219x+24 First multiply the coefficient of x^2 and the constant. That is, the coefficient of x^2 here is 2 nd constant is 24. 2*24=48 Then find two factors of 48 such that their sum is 19 and product is 48. That is if the factors are a and b a+b=19 a*b=48

happykiddo
 2 years ago
Best ResponseYou've already chosen the best response.0yeah but 24 and 2 dont add up to 19 or any of the other multiples i can think of for 48

ajprincess
 2 years ago
Best ResponseYou've already chosen the best response.1I think the expression u have given shoul be 2x^211x+48 and nt 2x^219x+48. plzz chck

happykiddo
 2 years ago
Best ResponseYou've already chosen the best response.0no its still 2x^219x+24

ajprincess
 2 years ago
Best ResponseYou've already chosen the best response.1ya u r right. Am sorry. Let me list out the factors of 48 1,2,3,4,6,8,12,16,24,48,1,2,3,4,6,8,12,16,24,48. Nw chck if u can find those numbers

happykiddo
 2 years ago
Best ResponseYou've already chosen the best response.0so the answer should be (2x3) (x16)..........not what the book gives me which is (x8) (2x3)

ajprincess
 2 years ago
Best ResponseYou've already chosen the best response.12x^219x+24 =2x^216x3x+24 =2x(x8)3(x8)

ajprincess
 2 years ago
Best ResponseYou've already chosen the best response.1After finding the numbers u have to split only the mid term using thm. Gettng t? @happykiddo

happykiddo
 2 years ago
Best ResponseYou've already chosen the best response.0oh i see where your going with this THANK YOU :D

ajprincess
 2 years ago
Best ResponseYou've already chosen the best response.1Glad to hear that nd welcome:)

happykiddo
 2 years ago
Best ResponseYou've already chosen the best response.0yay i just got two more problems right. i dont think i'll be needing more help : )

ajprincess
 2 years ago
Best ResponseYou've already chosen the best response.1Congrats for gettng ur problems rght:)
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