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happykiddo
 one year ago
Best ResponseYou've already chosen the best response.0i know the answer is (x8) (2x3).........but how exactly would i get that?

ajprincess
 one year ago
Best ResponseYou've already chosen the best response.12x^219x+24 First multiply the coefficient of x^2 and the constant. That is, the coefficient of x^2 here is 2 nd constant is 24. 2*24=48 Then find two factors of 48 such that their sum is 19 and product is 48. That is if the factors are a and b a+b=19 a*b=48

happykiddo
 one year ago
Best ResponseYou've already chosen the best response.0yeah but 24 and 2 dont add up to 19 or any of the other multiples i can think of for 48

ajprincess
 one year ago
Best ResponseYou've already chosen the best response.1I think the expression u have given shoul be 2x^211x+48 and nt 2x^219x+48. plzz chck

happykiddo
 one year ago
Best ResponseYou've already chosen the best response.0no its still 2x^219x+24

ajprincess
 one year ago
Best ResponseYou've already chosen the best response.1ya u r right. Am sorry. Let me list out the factors of 48 1,2,3,4,6,8,12,16,24,48,1,2,3,4,6,8,12,16,24,48. Nw chck if u can find those numbers

happykiddo
 one year ago
Best ResponseYou've already chosen the best response.0so the answer should be (2x3) (x16)..........not what the book gives me which is (x8) (2x3)

ajprincess
 one year ago
Best ResponseYou've already chosen the best response.12x^219x+24 =2x^216x3x+24 =2x(x8)3(x8)

ajprincess
 one year ago
Best ResponseYou've already chosen the best response.1After finding the numbers u have to split only the mid term using thm. Gettng t? @happykiddo

happykiddo
 one year ago
Best ResponseYou've already chosen the best response.0oh i see where your going with this THANK YOU :D

happykiddo
 one year ago
Best ResponseYou've already chosen the best response.0this really helped.

ajprincess
 one year ago
Best ResponseYou've already chosen the best response.1Glad to hear that nd welcome:)

happykiddo
 one year ago
Best ResponseYou've already chosen the best response.0yay i just got two more problems right. i dont think i'll be needing more help : )

ajprincess
 one year ago
Best ResponseYou've already chosen the best response.1Congrats for gettng ur problems rght:)
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