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anonymous
 3 years ago
Simplify: sqrt c (3 + 2sqrt 5)
5 sqrt 5c
C sqrt 3 + c sqrt 10
3 sqrt c + 2 sqrt 5c
3 sqrt c + 2c sqrt 5
anonymous
 3 years ago
Simplify: sqrt c (3 + 2sqrt 5) 5 sqrt 5c C sqrt 3 + c sqrt 10 3 sqrt c + 2 sqrt 5c 3 sqrt c + 2c sqrt 5

This Question is Closed

ajprincess
 3 years ago
Best ResponseYou've already chosen the best response.0Use distributive property a(b+c)+ab+ac Here a=sqrtc b=3 c=2sqrt5 Does that help? @Solmyr

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0srry had to do something

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Sqrt c(3 + 2 sqrt 5) + sqrt c(3) + sqrt c(2 sqrt 5)

phi
 3 years ago
Best ResponseYou've already chosen the best response.1it is best to put the numbers in front of the sq rt sign, it's less confusing Sqrt c(3 + 2 sqrt 5) = 3sqrt c + 2 sqrt c sqrt 5 you should know that \[ \sqrt{a} \cdot \sqrt{b} = \sqrt{a\cdot b} \] That rule means you can combine sqrt(c)*sqrt(5)

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0i was thinking that the answer was A and still thinking because of what u showed

phi
 3 years ago
Best ResponseYou've already chosen the best response.1I thought A was B. But A is not correct. the answer is 3sqrt c + 2 sqrt c sqrt 5 or a simplified version of this

phi
 3 years ago
Best ResponseYou've already chosen the best response.1rewrite \[ 3\sqrt c + 2 \sqrt c \sqrt 5\] by putting the c and 5 inside the same sqrt

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0do you have time to help me with two more?

phi
 3 years ago
Best ResponseYou've already chosen the best response.1first, did you finish this one? put the c and 5 inside the same sqrt \[3\sqrt c + 2 \sqrt c \sqrt 5\]

phi
 3 years ago
Best ResponseYou've already chosen the best response.1you can do that only for the 2nd term.

phi
 3 years ago
Best ResponseYou've already chosen the best response.1ok, that should match one of your choices

phi
 3 years ago
Best ResponseYou've already chosen the best response.1so to do this, you distributed and then you combined two sq rt's

phi
 3 years ago
Best ResponseYou've already chosen the best response.1please post your other question separately
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