anonymous
  • anonymous
Capacitors in series and in parallel
Physics
jamiebookeater
  • jamiebookeater
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get this expert

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this
and thousands of other questions

anonymous
  • anonymous
|dw:1362354546520:dw| @experimentX
anonymous
  • anonymous
no let me try it
experimentX
  • experimentX
|dw:1362354809409:dw|

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

anonymous
  • anonymous
|dw:1362354804183:dw|
anonymous
  • anonymous
oh ok
anonymous
  • anonymous
An ok way to remember it is that capacitors in series add like resistors in parallel. Other way around too
anonymous
  • anonymous
ok since they're in parallel, the voltages are the same. \[V=V_1=V_2\] \[Q=Q_1+Q_2\] \[C=\frac{Q}{V}\] \[C_1=\frac{Q_1}{V_1}=\frac{Q_1}{V}\] \[C_2=\frac{Q_2}{V_2}=\frac{Q_2}{V}\] \[CV=C_1V+C_2V\] \[C\cancel{V}=C_1\cancel{V}+C_2\cancel V\] C=C_1+C_2
anonymous
  • anonymous
but they have different capacitances.....hmmm?
anonymous
  • anonymous
oh I add the capacitances to get C....the total capacitance of the capacitors in parallel \[C=6 \mu F\]
experimentX
  • experimentX
yeah yeah ... parallel is like absolute capitalism!!
anonymous
  • anonymous
|dw:1362355380229:dw| LOL!!!!!
anonymous
  • anonymous
oh ok let's see|dw:1362355422603:dw| \[C=\frac{Q}{V}\] \[C_1=\frac{Q}{V_1}\] \[C_2=\frac{Q}{V_2}\] \[Q=Q_1=Q_2\] \[V=V_1+V_2\] \[\frac Q C=\frac{Q}{C_1}+\frac{Q}{C_2}\] \[\frac {\cancel Q} C=\frac{\cancel Q}{C_1}+\frac{\cancel Q}{C_2}\] \[\frac 1 C=\frac 1 {C_1}+\frac 1{C_2}\]
anonymous
  • anonymous
\[\frac 1 C=\frac 1 6+\frac 2 6=\frac 3 6\] \[C=2\]

Looking for something else?

Not the answer you are looking for? Search for more explanations.