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tomo Group TitleBest ResponseYou've already chosen the best response.0
is there supposed to be a b = [3,5]
 one year ago

burhan101 Group TitleBest ResponseYou've already chosen the best response.0
yup, typo *
 one year ago

amistre64 Group TitleBest ResponseYou've already chosen the best response.1
magnitude of the cross product i think is a way to determine it
 one year ago

amistre64 Group TitleBest ResponseYou've already chosen the best response.1
ab sin(t); where t is the angle between a and b
 one year ago

amistre64 Group TitleBest ResponseYou've already chosen the best response.1
\[sin(t)=\frac{axb}{ab}\] so yeah, the magnitude of the cross product
 one year ago

burhan101 Group TitleBest ResponseYou've already chosen the best response.0
@amistre64 how can i do the cross product when only x and y are given ?
 one year ago

amistre64 Group TitleBest ResponseYou've already chosen the best response.1
plug in z=0 :)
 one year ago

burhan101 Group TitleBest ResponseYou've already chosen the best response.0
ohhh! .. facepalm
 one year ago

amistre64 Group TitleBest ResponseYou've already chosen the best response.1
a= [1,4], = [3,5] x 1 3 y 4 5 z 0 0 x = 00 y = 00 z = 5+12 the magnitude of [0, 0, 7 ] = 7
 one year ago

amistre64 Group TitleBest ResponseYou've already chosen the best response.1
of course the cross of R^2 simplifies as the determinant
 one year ago

burhan101 Group TitleBest ResponseYou've already chosen the best response.0
Okay thanks ! :)
 one year ago

burhan101 Group TitleBest ResponseYou've already chosen the best response.0
wouldnt axb = 0 ? :S
 one year ago

amistre64 Group TitleBest ResponseYou've already chosen the best response.1
my teacher did an R^2 cross a few semesters ago, and I was like, aint it just the determinant? and she was like or just plug in z=0 :)
 one year ago

burhan101 Group TitleBest ResponseYou've already chosen the best response.0
yeah i think its easier to plug in the zero :P
 one year ago

amistre64 Group TitleBest ResponseYou've already chosen the best response.1
have fun ;)
 one year ago
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