burhan101
Area of a parallelogram a= [1,4], = [3,5]



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tomo
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is there supposed to be a b = [3,5]

burhan101
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yup, typo *

amistre64
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magnitude of the cross product i think is a way to determine it

amistre64
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ab sin(t); where t is the angle between a and b

amistre64
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\[sin(t)=\frac{axb}{ab}\]
so yeah, the magnitude of the cross product

burhan101
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@amistre64 how can i do the cross product when only x and y are given ?

amistre64
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plug in z=0 :)

burhan101
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ohhh! .. facepalm

amistre64
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a= [1,4], = [3,5]
x 1 3
y 4 5
z 0 0
x = 00
y = 00
z = 5+12
the magnitude of [0, 0, 7 ] = 7

amistre64
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of course the cross of R^2 simplifies as the determinant

burhan101
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Okay thanks ! :)

burhan101
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wouldnt axb = 0 ? :S

burhan101
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oh nvm

amistre64
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my teacher did an R^2 cross a few semesters ago, and I was like, aint it just the determinant? and she was like or just plug in z=0 :)

burhan101
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yeah i think its easier to plug in the zero :P

amistre64
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have fun ;)