anonymous
  • anonymous
Area of a parallelogram a= [1,-4], = [3,-5]
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
is there supposed to be a b = [3,-5]
anonymous
  • anonymous
yup, typo *
amistre64
  • amistre64
magnitude of the cross product i think is a way to determine it

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amistre64
  • amistre64
|a||b| sin(t); where t is the angle between a and b
amistre64
  • amistre64
\[sin(t)=\frac{|axb|}{|a||b|}\] so yeah, the magnitude of the cross product
anonymous
  • anonymous
@amistre64 how can i do the cross product when only x and y are given ?
amistre64
  • amistre64
plug in z=0 :)
anonymous
  • anonymous
ohhh! .. facepalm
amistre64
  • amistre64
a= [1,-4], = [3,-5] x 1 3 y -4 -5 z 0 0 x = 0-0 -y = 0-0 z = -5+12 the magnitude of [0, 0, 7 ] = 7
amistre64
  • amistre64
of course the cross of R^2 simplifies as the determinant
anonymous
  • anonymous
Okay thanks ! :)
anonymous
  • anonymous
wouldnt axb = 0 ? :S
anonymous
  • anonymous
oh nvm
amistre64
  • amistre64
my teacher did an R^2 cross a few semesters ago, and I was like, aint it just the determinant? and she was like or just plug in z=0 :)
anonymous
  • anonymous
yeah i think its easier to plug in the zero :P
amistre64
  • amistre64
have fun ;)

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