anonymous
  • anonymous
If an object is pushed 5m along a certain incline, its height above the ground increases by 2m. If the incline were frictionless it would require a force of 196N exerted parallel to the incline to push a 50kg crate up the incline at a constant speed. How much work would be done in pushing the crate up the incline?
Physics
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
schrodinger
  • schrodinger
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
Work is equal to force times displacement times the cosine of the angle. W=f*s*cos(theta) The tricky part of your problem is finding theta. Since I'm on my phone I can't draw the picture as I would like to, but you are going to take the arctan of 5/2 to find the angle. Tan^-1(5/2)=calculated angle. The rest of this problem is plug and chug. W=196N*5m*calculated angle
anonymous
  • anonymous
I'm sorry, I said arc tan and it should be arcsin because sin=opp/hyp. And work will be: W=196N*5m*cos(calculated angle) Sorry for the mistakes. All should be correct now

Looking for something else?

Not the answer you are looking for? Search for more explanations.