shaqadry
integrate (1x) ln x dx



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TuringTest
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by parts

tomo
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break it up into two integral (ln(x)) and x(ln(x))
for the second part do a u substitution where u = ln(x); du = dx/x

tomo
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not sure if parts is necessary @TuringTest

shaqadry
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not using the udv = uv  vdu?

wio
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I think parts is best here.

TuringTest
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yes, use dv=1x and u=ln(x)

shaqadry
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can you show me the solution? i've done mine but it seems incorrect

TuringTest
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no we cannot give direct answers here, why don't you try and show us how you do?

shaqadry
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its pretty long. but my answer is
ln x [ x  (x^2/2) ]  x  (x^2/4) + C

tomo
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yeah, u sub wouldn't work since u = ln(x), du = dx/x , x*du = dx.

TuringTest
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but that answer is correct :)

TuringTest
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oh I think except for a minus sign...
ln x [ x  (x^2/2) ]  x + (x^2/4) + C

shaqadry
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thank you!!

TuringTest
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welcome :)