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integrate (1-x) ln x dx

Mathematics
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by parts
break it up into two integral (ln(x)) and -x(ln(x)) for the second part do a u substitution where u = ln(x); du = dx/x
not sure if parts is necessary @TuringTest

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Other answers:

not using the udv = uv - vdu?
I think parts is best here.
yes, use dv=1-x and u=ln(x)
can you show me the solution? i've done mine but it seems incorrect
no we cannot give direct answers here, why don't you try and show us how you do?
its pretty long. but my answer is ln x [ x - (x^2/2) ] - x - (x^2/4) + C
yeah, u sub wouldn't work since u = ln(x), du = dx/x , x*du = dx.
but that answer is correct :)
oh I think except for a minus sign... ln x [ x - (x^2/2) ] - x + (x^2/4) + C
thank you!!
welcome :)

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