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shaqadry

  • 3 years ago

integrate (1-x) ln x dx

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  1. TuringTest
    • 3 years ago
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    by parts

  2. tomo
    • 3 years ago
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    break it up into two integral (ln(x)) and -x(ln(x)) for the second part do a u substitution where u = ln(x); du = dx/x

  3. tomo
    • 3 years ago
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    not sure if parts is necessary @TuringTest

  4. shaqadry
    • 3 years ago
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    not using the udv = uv - vdu?

  5. wio
    • 3 years ago
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    I think parts is best here.

  6. TuringTest
    • 3 years ago
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    yes, use dv=1-x and u=ln(x)

  7. shaqadry
    • 3 years ago
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    can you show me the solution? i've done mine but it seems incorrect

  8. TuringTest
    • 3 years ago
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    no we cannot give direct answers here, why don't you try and show us how you do?

  9. shaqadry
    • 3 years ago
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    its pretty long. but my answer is ln x [ x - (x^2/2) ] - x - (x^2/4) + C

  10. tomo
    • 3 years ago
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    yeah, u sub wouldn't work since u = ln(x), du = dx/x , x*du = dx.

  11. TuringTest
    • 3 years ago
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    but that answer is correct :)

  12. TuringTest
    • 3 years ago
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    oh I think except for a minus sign... ln x [ x - (x^2/2) ] - x + (x^2/4) + C

  13. shaqadry
    • 3 years ago
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    thank you!!

  14. TuringTest
    • 3 years ago
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    welcome :)

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