anonymous
  • anonymous
integrate (1-x) ln x dx
Mathematics
katieb
  • katieb
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TuringTest
  • TuringTest
by parts
anonymous
  • anonymous
break it up into two integral (ln(x)) and -x(ln(x)) for the second part do a u substitution where u = ln(x); du = dx/x
anonymous
  • anonymous
not sure if parts is necessary @TuringTest

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anonymous
  • anonymous
not using the udv = uv - vdu?
anonymous
  • anonymous
I think parts is best here.
TuringTest
  • TuringTest
yes, use dv=1-x and u=ln(x)
anonymous
  • anonymous
can you show me the solution? i've done mine but it seems incorrect
TuringTest
  • TuringTest
no we cannot give direct answers here, why don't you try and show us how you do?
anonymous
  • anonymous
its pretty long. but my answer is ln x [ x - (x^2/2) ] - x - (x^2/4) + C
anonymous
  • anonymous
yeah, u sub wouldn't work since u = ln(x), du = dx/x , x*du = dx.
TuringTest
  • TuringTest
but that answer is correct :)
TuringTest
  • TuringTest
oh I think except for a minus sign... ln x [ x - (x^2/2) ] - x + (x^2/4) + C
anonymous
  • anonymous
thank you!!
TuringTest
  • TuringTest
welcome :)

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