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dellzasaur

  • 3 years ago

How to solve 2e^ln x + 3 = 6?

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  1. anonymous
    • 3 years ago
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    at the risk of repeating myself, is it \[2e^{\ln(x)+3}\] or \[2e^{\ln(x)}+3\]?

  2. dellzasaur
    • 3 years ago
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    I replied to you, but it's the second one. @satellite73

  3. anonymous
    • 3 years ago
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    ah ok

  4. anonymous
    • 3 years ago
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    then start with \[2x+3=6\] and solve for \(x\) because \(e^{\ln(x)}=x\)

  5. dellzasaur
    • 3 years ago
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    so would I just have 2x = 3 and then divide the 3 by 2?

  6. dellzasaur
    • 3 years ago
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    @satellite73

  7. ByteMe
    • 3 years ago
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    yes (to your last post)

  8. RadEn
    • 3 years ago
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    agree ^^

  9. dellzasaur
    • 3 years ago
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    Thanks everyone! :) @byteme @RadEn @satellite73

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