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How to solve 2e^ln x + 3 = 6?

Mathematics
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at the risk of repeating myself, is it \[2e^{\ln(x)+3}\] or \[2e^{\ln(x)}+3\]?
I replied to you, but it's the second one. @satellite73
ah ok

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Other answers:

then start with \[2x+3=6\] and solve for \(x\) because \(e^{\ln(x)}=x\)
so would I just have 2x = 3 and then divide the 3 by 2?
yes (to your last post)
agree ^^
Thanks everyone! :) @byteme @RadEn @satellite73

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