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dellzasaur

How to solve 2e^ln x + 3 = 6?

  • one year ago
  • one year ago

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  1. satellite73
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    at the risk of repeating myself, is it \[2e^{\ln(x)+3}\] or \[2e^{\ln(x)}+3\]?

    • one year ago
  2. dellzasaur
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    I replied to you, but it's the second one. @satellite73

    • one year ago
  3. satellite73
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    ah ok

    • one year ago
  4. satellite73
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    then start with \[2x+3=6\] and solve for \(x\) because \(e^{\ln(x)}=x\)

    • one year ago
  5. dellzasaur
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    so would I just have 2x = 3 and then divide the 3 by 2?

    • one year ago
  6. dellzasaur
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    @satellite73

    • one year ago
  7. ByteMe
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    yes (to your last post)

    • one year ago
  8. RadEn
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    agree ^^

    • one year ago
  9. dellzasaur
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    Thanks everyone! :) @byteme @RadEn @satellite73

    • one year ago
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