## dellzasaur How to solve 2e^ln x + 3 = 6? one year ago one year ago

1. satellite73

at the risk of repeating myself, is it $2e^{\ln(x)+3}$ or $2e^{\ln(x)}+3$?

2. dellzasaur

I replied to you, but it's the second one. @satellite73

3. satellite73

ah ok

4. satellite73

then start with $2x+3=6$ and solve for $$x$$ because $$e^{\ln(x)}=x$$

5. dellzasaur

so would I just have 2x = 3 and then divide the 3 by 2?

6. dellzasaur

@satellite73

7. ByteMe