dellzasaur
How to solve 2e^ln x + 3 = 6?



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anonymous
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at the risk of repeating myself, is it
\[2e^{\ln(x)+3}\] or
\[2e^{\ln(x)}+3\]?

dellzasaur
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I replied to you, but it's the second one. @satellite73

anonymous
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ah ok

anonymous
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then start with
\[2x+3=6\] and solve for \(x\) because \(e^{\ln(x)}=x\)

dellzasaur
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so would I just have 2x = 3 and then divide the 3 by 2?

dellzasaur
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@satellite73

ByteMe
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yes (to your last post)

RadEn
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agree ^^

dellzasaur
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Thanks everyone! :) @byteme @RadEn @satellite73