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jdlandreth
 2 years ago
you, in your new red Porsche, decide to make a 160km trip to Carolina Beach, traveling at 80km?hr. Your make a return trip at a rate of 48km?hr. What was your average speed for the entire trip?
jdlandreth
 2 years ago
you, in your new red Porsche, decide to make a 160km trip to Carolina Beach, traveling at 80km?hr. Your make a return trip at a rate of 48km?hr. What was your average speed for the entire trip?

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satellite73
 2 years ago
Best ResponseYou've already chosen the best response.0figure out the total time, and the total distance divide the total distance by the total time

satellite73
 2 years ago
Best ResponseYou've already chosen the best response.0ok it was easy but i got it wrong total distance is \(2\times 160=320\)

satellite73
 2 years ago
Best ResponseYou've already chosen the best response.0time going in your new red porche is \(\frac{160}{80}=2\)

satellite73
 2 years ago
Best ResponseYou've already chosen the best response.0how about the time returning?

jdlandreth
 2 years ago
Best ResponseYou've already chosen the best response.0ugh i don't know cause it comes out as a decimal?

satellite73
 2 years ago
Best ResponseYou've already chosen the best response.0much easier (believe it or not) if you leave it as a fraction

satellite73
 2 years ago
Best ResponseYou've already chosen the best response.0in other words, take \(\frac{160}{48}\) and instead of writing it as a repeating decimal, reduce it to \(\frac{10}{3}\)

jdlandreth
 2 years ago
Best ResponseYou've already chosen the best response.0okay so? then do i leave the other as 2? or 160/2?

satellite73
 2 years ago
Best ResponseYou've already chosen the best response.0now the next job is to total up the time, in other words compute \[2+\frac{10}{3}\] leave it as a fraction

satellite73
 2 years ago
Best ResponseYou've already chosen the best response.0right and now speed is distance divided by rate

satellite73
 2 years ago
Best ResponseYou've already chosen the best response.0so your final job is \[320\div \frac{16}{3}\]

jdlandreth
 2 years ago
Best ResponseYou've already chosen the best response.0So the average is 60?

satellite73
 2 years ago
Best ResponseYou've already chosen the best response.0that is what i get too

jdlandreth
 2 years ago
Best ResponseYou've already chosen the best response.0kay good. Thank you!!

satellite73
 2 years ago
Best ResponseYou've already chosen the best response.0notice two things 1) the average speed is not the "average of the speeds" and 2) the 160 is a red herring if you really want to impress your math teacher, show that it works no matter how far you drive

satellite73
 2 years ago
Best ResponseYou've already chosen the best response.0you could drive 160 miles or 100 miles or 3,000 miles or \(m\) miles, the average will still be 60

jdlandreth
 2 years ago
Best ResponseYou've already chosen the best response.0Okay Thank you soo much. =)

satellite73
 2 years ago
Best ResponseYou've already chosen the best response.0try it with \(m\) you get \[\frac{2m}{\frac{m}{80}+\frac{m}{48}}=60\] after some algebra
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