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you have to do four multiplications

I need to multiply

\[x^3\times x^3\] is the first one

x^6? do I add the exponents?

then \(x^3\times (-y^2)\)

yes

then \(x^3\times y^2\)

and finally \(y^2\times (-y)^2\)

x^6-y^4?

you will notice that middle terms add up to zero, so you are only left with
\[x^6-y^4\]

yes

it is always true that \((a+b)(a-b)=a^2-b^2\)

see, all I need is confidence and your great guidings! :) I might make it after all. LOL

you can also use a table to help you multiply
|dw:1362367881354:dw|

Hi Jim. thank you, that helps as well. :)

great explanation. I need all the tips I can get. thank you! :)

you're welcome