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ksandoval

  • 3 years ago

use dy/dt = kt and derive the formula for y

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  1. anonymous
    • 3 years ago
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    \[\frac{dy}{dt}=kt\] \[y=\frac{k}{2}t^2\] i guess, plus some arbitrary constant

  2. tomo
    • 3 years ago
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    dy/dt = kt (1/k)*dy = t * dt integral(1/k dy) = integral(t * dt) //1/k is a constant (1/k)*integral(dy) = (t^2)/2 (1/k)*y = (t^2)/2 y/k = (t^2)/2 y = (k*t^2)/2

  3. ksandoval
    • 3 years ago
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    @satellite73 the answer is\[y =y_{0}e ^{kt}\] which is why i am very confused...

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