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## ksandoval Group Title use dy/dt = kt and derive the formula for y one year ago one year ago

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1. satellite73 Group Title

$\frac{dy}{dt}=kt$ $y=\frac{k}{2}t^2$ i guess, plus some arbitrary constant

2. tomo Group Title

dy/dt = kt (1/k)*dy = t * dt integral(1/k dy) = integral(t * dt) //1/k is a constant (1/k)*integral(dy) = (t^2)/2 (1/k)*y = (t^2)/2 y/k = (t^2)/2 y = (k*t^2)/2

3. ksandoval Group Title

@satellite73 the answer is$y =y_{0}e ^{kt}$ which is why i am very confused...