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satellite73 Group TitleBest ResponseYou've already chosen the best response.0
\[\frac{dy}{dt}=kt\] \[y=\frac{k}{2}t^2\] i guess, plus some arbitrary constant
 one year ago

tomo Group TitleBest ResponseYou've already chosen the best response.0
dy/dt = kt (1/k)*dy = t * dt integral(1/k dy) = integral(t * dt) //1/k is a constant (1/k)*integral(dy) = (t^2)/2 (1/k)*y = (t^2)/2 y/k = (t^2)/2 y = (k*t^2)/2
 one year ago

ksandoval Group TitleBest ResponseYou've already chosen the best response.0
@satellite73 the answer is\[y =y_{0}e ^{kt}\] which is why i am very confused...
 one year ago
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