Vane11 2 years ago Decided to upload a pic since it'd be confusing to write it out I got stuck about halfway

1. Vane11

2. satellite73

$\frac{(m^4z^3)^{-2}}{(m^5z)^{-1}}$?

3. Vane11

yep :)

4. satellite73

you can start any way you like, but maybe the simplest method is to flip everything and make the exponents positive

5. satellite73

$\frac{(m^5z)}{(m^4z^3)^2}$

6. satellite73

now multiply each exponent in the denominator by 2

7. satellite73

$\frac{m^5z}{m^8z^6}$

8. satellite73

then cancel away $\frac{1}{m^3z^5}$ will finish it

9. Vane11

thanks! I had forgotten about the flipping around and was trying to do it the original way which was much more confusing

10. satellite73

yeah sometimes it is not clear what is easiest to do first