## Vane11 3 years ago Decided to upload a pic since it'd be confusing to write it out I got stuck about halfway

1. Vane11

2. anonymous

$\frac{(m^4z^3)^{-2}}{(m^5z)^{-1}}$?

3. Vane11

yep :)

4. anonymous

you can start any way you like, but maybe the simplest method is to flip everything and make the exponents positive

5. anonymous

$\frac{(m^5z)}{(m^4z^3)^2}$

6. anonymous

now multiply each exponent in the denominator by 2

7. anonymous

$\frac{m^5z}{m^8z^6}$

8. anonymous

then cancel away $\frac{1}{m^3z^5}$ will finish it

9. Vane11

thanks! I had forgotten about the flipping around and was trying to do it the original way which was much more confusing

10. anonymous

yeah sometimes it is not clear what is easiest to do first