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\[\frac{(m^4z^3)^{-2}}{(m^5z)^{-1}}\]?

yep :)

\[\frac{(m^5z)}{(m^4z^3)^2}\]

now multiply each exponent in the denominator by 2

\[\frac{m^5z}{m^8z^6}\]

then cancel away
\[\frac{1}{m^3z^5}\] will finish it

yeah sometimes it is not clear what is easiest to do first