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twirlere Group Title

f(x)=(x^2-3x-4)/(x-2) Find points of increase and decrease and all relative extrema.

  • one year ago
  • one year ago

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  1. satellite73 Group Title
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    you don't really need any calculus for this one

    • one year ago
  2. Xavier Group Title
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    Try factoring the numerator

    • one year ago
  3. satellite73 Group Title
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    it is a rational function with a slant asymptote at \(x-1\)

    • one year ago
  4. satellite73 Group Title
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    it is always increasing

    • one year ago
  5. satellite73 Group Title
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    you could take the derivative and get \[\frac{x^2-4x+10}{(x-2)^2}\] but the denominator is never negative, and neither is the numerator ( you can check that it has no zeros)

    • one year ago
  6. satellite73 Group Title
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    if you remember plotting rational functions in pre calc you may remember what something like this looks like

    • one year ago
  7. twirlere Group Title
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    That's the derivative that I got also. I was trying to find the critical points from this...

    • one year ago
  8. twirlere Group Title
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    So what would the critical points be?

    • one year ago
  9. saloniiigupta95 Group Title
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    Factorise the Numerator... Can you??? Then the critical points for an expression like this... \[(x-a)(x-b)/ (x-c) \] are a,b and c...

    • one year ago
  10. twirlere Group Title
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    I can't factor \[x^2-4x-10\]

    • one year ago
  11. saloniiigupta95 Group Title
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    You are supposed to factor x^2 - 3x-4 ... I think your question says so...

    • one year ago
  12. twirlere Group Title
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    Into... (x-2)(x-2)...?

    • one year ago
  13. saloniiigupta95 Group Title
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    x^2 - 3x - 4 =x^2 - 4x +x -4 = x(x-4) +1(x-4) = (x-4) (x+1)

    • one year ago
  14. twirlere Group Title
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    And critical points are then x=4 and x=-1

    • one year ago
  15. twirlere Group Title
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    I have to find the first derivative then factor

    • one year ago
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