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anonymous
 3 years ago
A parallelogram has and area of 300 cm squared, the side lengths are 90 cm and 30 cm. What are the measures of the angle?
anonymous
 3 years ago
A parallelogram has and area of 300 cm squared, the side lengths are 90 cm and 30 cm. What are the measures of the angle?

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anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0dw:1362374611174:dw Can you express the area of the parallelogram in terms of these values. Also the measure of the angle based on trig identities

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0I dont know what to do with it at all :S

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0That was all the given information, how an i supposed to find any angles?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Well what is the measure of the angle marked above in terms of the values and variables. Use a rig identity

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0How tho, i dont understand

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0theres not enough information given

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Can you express the area of the parallelogram in terms of the given values and the variable h we made up to represent the height?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0The area of a parallelogram is not side * size. It's base * height You can imagine splitting it into two triangles across the diagonal

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Yeah but there's no height given

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0That's why we are using a variable that we'll solve for. Express the area in terms of the given information and the variable h

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0We know the length is 90 and width is 30. We need to find the measures of the angles. We also know that the area is 300. Area of parallelogram = L x h (H is height, not the side length of 30) We know Area is 300 and L = 90, but we don't know the height. So we can solve for h. 300 = 90h h = 300/90 = 10/3 Now that we know the height, we can figure out the angles. If you look at Xavier's diagram and the part that he labelled as "angle", that angle is also part of a triangle. That triangle has the height 10/3, same as the parallelogram, and a hypotenuse of 30, which is the other side length of the parallegram. 10/3 is the side opposite to the angle, and 30 is the hypotenuse. From SOH CAH TOA, we can use sine to figure out the angle. @burhan101 sin(x) = (10/3) / (30) = 10/90 = 1/9 We can use the inverse sine function to find angle x. x = sin^1(1/9) = 6.38 Another thing we should is that one obtuse and one acute angle of a parallelogram are supplementary, meaning they add up to 180. If we know angle x,which is the acute angle is 6.38 degrees, we can subtract this from 180 to find the other angle, let's call it y : 6.38 + y = 180 > y = 180  6.38 = 173.62 Therefore, the two angles x and y are x = 6.38 degrees, y = 173.62 degrees

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Area of a parallelogram is also magnitude of vector a and vector b

RadEn
 3 years ago
Best ResponseYou've already chosen the best response.1u can use the law of sin : dw:1362375710504:dw

RadEn
 3 years ago
Best ResponseYou've already chosen the best response.1solve for theta after u got the value of sin(theta)

RadEn
 3 years ago
Best ResponseYou've already chosen the best response.1then for the other angle, just use the property of "consecutive interior angle" they sum 180 degrees, let the other angle is alpha : dw:1362376183926:dw
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