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Please tell me if this is right...
Solve the logarithmic equation:
log_4(x18) + log_4 (x3) = 2
log_4((x18)(x3)=4^2
x^221x+54=16
x^221x+38=0
(x2)(x19)=0
x=2, x=19 < Answer
 one year ago
 one year ago
Please tell me if this is right... Solve the logarithmic equation: log_4(x18) + log_4 (x3) = 2 log_4((x18)(x3)=4^2 x^221x+54=16 x^221x+38=0 (x2)(x19)=0 x=2, x=19 < Answer
 one year ago
 one year ago

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hartnnBest ResponseYou've already chosen the best response.1
your final answer is correct but the 2nd step will be log_4((x18)(x3)=2 then 3rd step x^221x+54=16 is correct
 one year ago

hartnnBest ResponseYou've already chosen the best response.1
or your 2nd step could be log_4((x18)(x3)=log_4 (4^2)
 one year ago

FakshonBest ResponseYou've already chosen the best response.0
yea I did that but I skipped the step on here. I wrote that on my paper.
 one year ago

hartnnBest ResponseYou've already chosen the best response.1
oh, wait i just realized, x=2 cannot be the answer
 one year ago

hartnnBest ResponseYou've already chosen the best response.1
because that would make x3 as negative then log (x3) will not be defined @Fakshon
 one year ago
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