anonymous
  • anonymous
Please tell me if this is right... Solve the logarithmic equation: log_4(x-18) + log_4 (x-3) = 2 log_4((x-18)(x-3)=4^2 x^2-21x+54=16 x^2-21x+38=0 (x-2)(x-19)=0 x=2, x=19 <--- Answer
Mathematics
schrodinger
  • schrodinger
See more answers at brainly.com
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get this expert

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this
and thousands of other questions

hartnn
  • hartnn
your final answer is correct but the 2nd step will be log_4((x-18)(x-3)=2 then 3rd step x^2-21x+54=16 is correct
hartnn
  • hartnn
or your 2nd step could be log_4((x-18)(x-3)=log_4 (4^2)
anonymous
  • anonymous
yea I did that but I skipped the step on here. I wrote that on my paper.

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

hartnn
  • hartnn
then you are correct
hartnn
  • hartnn
oh, wait i just realized, x=2 cannot be the answer
hartnn
  • hartnn
because that would make x-3 as negative then log (x-3) will not be defined @Fakshon

Looking for something else?

Not the answer you are looking for? Search for more explanations.