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Find an equation of the tangent line to the curve y=sin(7x)+cos(6x) at the point (pi/6,y(pi/6))

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do you know how to find slope of tangent at a point ?
I will first take the derivative of that equation and then plug in x. For some reason I'm still not getting the correct answer to this problem.
show your work, i'll spot the error.

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this way it'll get solved faster
7cos(7x)−6sin(6x) is the derivative. So plugging in pi/6 for x to get the slope. We get -6.062177826
ok, i get the same thing, thats your slope
So putting this is slope intercept form you get \[Y=-6.062177826x+b\] My only concern is with the y value being y(pi/6)
yes, to get y(pi/6) put x=pi/6 in y sin(7pi/6)+cos(6pi/6) = ...
wait where am i putting the pi/6?
to get y(pi/6) from y(x) =sin(7x)+cos(6x) just replace x = pi/6 there
so -1.5?
yup so point is (pi/6, -1.5) with slope = -6.06 now can u find the equation of line ?
So b=1.674148887 (I kept the full value of the slope in.) So the answer would be y=-6.062177826x+1.674148887
yes, i get the same answer.
Thank you very much for your help today.
welcome very much :)

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