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ajprincess
 one year ago
Best ResponseYou've already chosen the best response.1Using pythagoras' theorem u can find the length of the hypotenuse. a^2+b^2=c^2 Here a=2, b=3, c=? dw:1362407511223:dwdw:1362407540894:dw Does that help? @Atkinsoha

Atkinsoha
 one year ago
Best ResponseYou've already chosen the best response.0I did all of that.. I'm stuck on maybe how to solve it, since I can't seem to come up with any of the answers that are given.

ajprincess
 one year ago
Best ResponseYou've already chosen the best response.1What is the value of hypotenuse?

ajprincess
 one year ago
Best ResponseYou've already chosen the best response.1nw what is \(\cos\theta\)

ajprincess
 one year ago
Best ResponseYou've already chosen the best response.1yup:) what is \(\cos^2\theta\)?

Atkinsoha
 one year ago
Best ResponseYou've already chosen the best response.0That's were I'm lost apparently. 3^2 = 9 and the (√13)^2 = 13?

Atkinsoha
 one year ago
Best ResponseYou've already chosen the best response.0WAIT. Is it A? 5/13? because then it would be 2(9/13)1 which would be (18/13)1 and one would be 13/13 so it would be 5/13? A?

Atkinsoha
 one year ago
Best ResponseYou've already chosen the best response.0HOLY BEJEBOUS! Thank you so much! I guess I just needed someone to break it down!

Atkinsoha
 one year ago
Best ResponseYou've already chosen the best response.0Can you help me with this one? I'm sure it's really easy, but I've been gone from school.. so haven't learned it :P

ajprincess
 one year ago
Best ResponseYou've already chosen the best response.1let us say arcsinx=theta nd arccosx=beta so sin theta=x nd cos beta =x sin(arcsinx+arccosx)=sin(theta+beta) =sin theta*cos beta+sin beta * cos theta

ajprincess
 one year ago
Best ResponseYou've already chosen the best response.1cos theta=sqrt(1sin^2theta) sin beta=sqrt(1cos^2 beta) plug in the values and u will get the algebraic expression:)

Atkinsoha
 one year ago
Best ResponseYou've already chosen the best response.0Yeahh.. I don't understand at all. haha.

ajprincess
 one year ago
Best ResponseYou've already chosen the best response.1Really sorry. Hav to go nw. Please post this as a new ques. Hope some will sre help u.:) Really sorry
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