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ajprincess Group TitleBest ResponseYou've already chosen the best response.1
Using pythagoras' theorem u can find the length of the hypotenuse. a^2+b^2=c^2 Here a=2, b=3, c=? dw:1362407511223:dwdw:1362407540894:dw Does that help? @Atkinsoha
 one year ago

Atkinsoha Group TitleBest ResponseYou've already chosen the best response.0
I did all of that.. I'm stuck on maybe how to solve it, since I can't seem to come up with any of the answers that are given.
 one year ago

ajprincess Group TitleBest ResponseYou've already chosen the best response.1
What is the value of hypotenuse?
 one year ago

Atkinsoha Group TitleBest ResponseYou've already chosen the best response.0
(√13)? I hope..
 one year ago

ajprincess Group TitleBest ResponseYou've already chosen the best response.1
yup right:)
 one year ago

ajprincess Group TitleBest ResponseYou've already chosen the best response.1
nw what is \(\cos\theta\)
 one year ago

ajprincess Group TitleBest ResponseYou've already chosen the best response.1
yup:) what is \(\cos^2\theta\)?
 one year ago

Atkinsoha Group TitleBest ResponseYou've already chosen the best response.0
That's were I'm lost apparently. 3^2 = 9 and the (√13)^2 = 13?
 one year ago

Atkinsoha Group TitleBest ResponseYou've already chosen the best response.0
WAIT. Is it A? 5/13? because then it would be 2(9/13)1 which would be (18/13)1 and one would be 13/13 so it would be 5/13? A?
 one year ago

Atkinsoha Group TitleBest ResponseYou've already chosen the best response.0
HOLY BEJEBOUS! Thank you so much! I guess I just needed someone to break it down!
 one year ago

Atkinsoha Group TitleBest ResponseYou've already chosen the best response.0
Can you help me with this one? I'm sure it's really easy, but I've been gone from school.. so haven't learned it :P
 one year ago

ajprincess Group TitleBest ResponseYou've already chosen the best response.1
let us say arcsinx=theta nd arccosx=beta so sin theta=x nd cos beta =x sin(arcsinx+arccosx)=sin(theta+beta) =sin theta*cos beta+sin beta * cos theta
 one year ago

ajprincess Group TitleBest ResponseYou've already chosen the best response.1
cos theta=sqrt(1sin^2theta) sin beta=sqrt(1cos^2 beta) plug in the values and u will get the algebraic expression:)
 one year ago

Atkinsoha Group TitleBest ResponseYou've already chosen the best response.0
Yeahh.. I don't understand at all. haha.
 one year ago

ajprincess Group TitleBest ResponseYou've already chosen the best response.1
Really sorry. Hav to go nw. Please post this as a new ques. Hope some will sre help u.:) Really sorry
 one year ago
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