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anonymous
 3 years ago
PreCalc & Trig Question! (Picture below) please try to be as specific as possible.. as I have not been able to go to school for over a week and have missed all of these lessons!
anonymous
 3 years ago
PreCalc & Trig Question! (Picture below) please try to be as specific as possible.. as I have not been able to go to school for over a week and have missed all of these lessons!

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anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Try using the identity \[\sin(A+B)=\sin(A)\cos(B)+\sin(B)\cos(A)\]Then \[\sin^2(x)+\cos^2(x)=1\] See how far you get with that.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0I'm still lost.. how do you get from one to the other?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Right, if A = arcsin(x) and B = arccos(x), what would the addition identity give?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0=arcsin(x) arccos(x) + no idea because sin is not given for b?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Huh? Let: \[A=\sin^{1}(x) \textrm{ and } B=\cos^{1}(x)\]Then using the sum identity that I wrote: \[\sin(\sin^{1}(x) + \cos^{1}(x)) = \sin(\sin^{1}(x))\cos(\cos^{1}(x))+\sin(\cos^{1}(x))\cos(\sin^{1}(x))\]Follow up to here?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Ok.. From here, we know that sin(arcsin(x)) = x and cos(arccos(x)) = x, so: \[ = x^2 + \sin(\cos^{1}(x))\cos(\sin^{1}(x))\] Now you can write \[\sin(x)=\sqrt{1\cos^2(x)}\]and\[\cos(x)=\sqrt{1\sin^2(x)}\]Using the second identity that I wrote. Again, do you follow?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0okay, yes following so far.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Ok, so we now get \[=x^2 + \sqrt{1\cos^2(\cos^{1}(x))}\sqrt{1\sin^2(\sin^{1}(x))}\]\[=x^2 + \sqrt{1x^2}\sqrt{1x^2}\] Hopefully you can do the rest.. If there's anything you don't get, say so.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0so.. it ends up being? (√1)?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0!!?! I get it! Thank you so much!
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