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 one year ago
PreCalc & Trig Question! (Picture below) please try to be as specific as possible.. as I have not been able to go to school for over a week and have missed all of these lessons!
 one year ago
PreCalc & Trig Question! (Picture below) please try to be as specific as possible.. as I have not been able to go to school for over a week and have missed all of these lessons!

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bamsanks
 one year ago
Best ResponseYou've already chosen the best response.1Try using the identity \[\sin(A+B)=\sin(A)\cos(B)+\sin(B)\cos(A)\]Then \[\sin^2(x)+\cos^2(x)=1\] See how far you get with that.

Atkinsoha
 one year ago
Best ResponseYou've already chosen the best response.0I'm still lost.. how do you get from one to the other?

bamsanks
 one year ago
Best ResponseYou've already chosen the best response.1Right, if A = arcsin(x) and B = arccos(x), what would the addition identity give?

Atkinsoha
 one year ago
Best ResponseYou've already chosen the best response.0=arcsin(x) arccos(x) + no idea because sin is not given for b?

bamsanks
 one year ago
Best ResponseYou've already chosen the best response.1Huh? Let: \[A=\sin^{1}(x) \textrm{ and } B=\cos^{1}(x)\]Then using the sum identity that I wrote: \[\sin(\sin^{1}(x) + \cos^{1}(x)) = \sin(\sin^{1}(x))\cos(\cos^{1}(x))+\sin(\cos^{1}(x))\cos(\sin^{1}(x))\]Follow up to here?

bamsanks
 one year ago
Best ResponseYou've already chosen the best response.1Ok.. From here, we know that sin(arcsin(x)) = x and cos(arccos(x)) = x, so: \[ = x^2 + \sin(\cos^{1}(x))\cos(\sin^{1}(x))\] Now you can write \[\sin(x)=\sqrt{1\cos^2(x)}\]and\[\cos(x)=\sqrt{1\sin^2(x)}\]Using the second identity that I wrote. Again, do you follow?

Atkinsoha
 one year ago
Best ResponseYou've already chosen the best response.0okay, yes following so far.

bamsanks
 one year ago
Best ResponseYou've already chosen the best response.1Ok, so we now get \[=x^2 + \sqrt{1\cos^2(\cos^{1}(x))}\sqrt{1\sin^2(\sin^{1}(x))}\]\[=x^2 + \sqrt{1x^2}\sqrt{1x^2}\] Hopefully you can do the rest.. If there's anything you don't get, say so.

Atkinsoha
 one year ago
Best ResponseYou've already chosen the best response.0so.. it ends up being? (√1)?

Atkinsoha
 one year ago
Best ResponseYou've already chosen the best response.0!!?! I get it! Thank you so much!
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