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PreCalc & Trig Question! (Picture below) please try to be as specific as possible.. as I have not been able to go to school for over a week and have missed all of these lessons!
 one year ago
 one year ago
PreCalc & Trig Question! (Picture below) please try to be as specific as possible.. as I have not been able to go to school for over a week and have missed all of these lessons!
 one year ago
 one year ago

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bamsanksBest ResponseYou've already chosen the best response.1
Try using the identity \[\sin(A+B)=\sin(A)\cos(B)+\sin(B)\cos(A)\]Then \[\sin^2(x)+\cos^2(x)=1\] See how far you get with that.
 one year ago

AtkinsohaBest ResponseYou've already chosen the best response.0
I'm still lost.. how do you get from one to the other?
 one year ago

bamsanksBest ResponseYou've already chosen the best response.1
Right, if A = arcsin(x) and B = arccos(x), what would the addition identity give?
 one year ago

AtkinsohaBest ResponseYou've already chosen the best response.0
=arcsin(x) arccos(x) + no idea because sin is not given for b?
 one year ago

bamsanksBest ResponseYou've already chosen the best response.1
Huh? Let: \[A=\sin^{1}(x) \textrm{ and } B=\cos^{1}(x)\]Then using the sum identity that I wrote: \[\sin(\sin^{1}(x) + \cos^{1}(x)) = \sin(\sin^{1}(x))\cos(\cos^{1}(x))+\sin(\cos^{1}(x))\cos(\sin^{1}(x))\]Follow up to here?
 one year ago

bamsanksBest ResponseYou've already chosen the best response.1
Ok.. From here, we know that sin(arcsin(x)) = x and cos(arccos(x)) = x, so: \[ = x^2 + \sin(\cos^{1}(x))\cos(\sin^{1}(x))\] Now you can write \[\sin(x)=\sqrt{1\cos^2(x)}\]and\[\cos(x)=\sqrt{1\sin^2(x)}\]Using the second identity that I wrote. Again, do you follow?
 one year ago

AtkinsohaBest ResponseYou've already chosen the best response.0
okay, yes following so far.
 one year ago

bamsanksBest ResponseYou've already chosen the best response.1
Ok, so we now get \[=x^2 + \sqrt{1\cos^2(\cos^{1}(x))}\sqrt{1\sin^2(\sin^{1}(x))}\]\[=x^2 + \sqrt{1x^2}\sqrt{1x^2}\] Hopefully you can do the rest.. If there's anything you don't get, say so.
 one year ago

AtkinsohaBest ResponseYou've already chosen the best response.0
so.. it ends up being? (√1)?
 one year ago

AtkinsohaBest ResponseYou've already chosen the best response.0
!!?! I get it! Thank you so much!
 one year ago
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