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elexusvanderhorst Group Title

please help question is attached below

  • one year ago
  • one year ago

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  1. elexusvanderhorst Group Title
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    • one year ago
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  2. zepp Group Title
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    If Mitch wants to have 10 spare bars and he could only afford 28, how many candy bars his friends could have?

    • one year ago
  3. elexusvanderhorst Group Title
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    18

    • one year ago
  4. zepp Group Title
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    Correct, now if you want to distribute equally the amount of candy among 'f' friend, how many candy bars will each friend get?

    • one year ago
  5. elexusvanderhorst Group Title
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    9

    • one year ago
  6. zepp Group Title
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    We do not know how many friends he has, he has 'f' friends.

    • one year ago
  7. elexusvanderhorst Group Title
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    but it says 2 to each friend so i did 18/2

    • one year ago
  8. zepp Group Title
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    Yes, 9 friends, but each friend would get 2 bars, correct?

    • one year ago
  9. zepp Group Title
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    But let's suppose we do not know and we do not want to solve the problem, we'll keep f as the number of friends, you agree that, 18/2 = f

    • one year ago
  10. elexusvanderhorst Group Title
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    yes

    • one year ago
  11. zepp Group Title
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    So in words, the amount of candy bars Mitch wants to keep for himself, added to the amount of candy bars his friends would get, gives 28

    • one year ago
  12. zepp Group Title
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    Amount of candy bars Mitch wants to keep for himself is 10 Amount of candy bars his friend would get, in term of the variable 'f', would the the number of friend (f) times the number of candies each of them would receive, 2, thus, 2f Therefore the equation to express this would be?

    • one year ago
  13. elexusvanderhorst Group Title
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    so which equation 2f-10=28?

    • one year ago
  14. zepp Group Title
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    Partly correct, it's an adding operation, not a subtracting operation

    • one year ago
  15. elexusvanderhorst Group Title
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    2f+10=28

    • one year ago
  16. zepp Group Title
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    Yep you got it

    • one year ago
  17. elexusvanderhorst Group Title
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    ok thank you so much

    • one year ago
  18. zepp Group Title
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    np

    • one year ago
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