A community for students. Sign up today!
Here's the question you clicked on:
 0 viewing

This Question is Closed

satellite73
 one year ago
Best ResponseYou've already chosen the best response.0\[2\cos(x)\sin(x)\]is your first derivative take the derivative of that one, using the product rule

onegirl
 one year ago
Best ResponseYou've already chosen the best response.0@satellite73 it will be 2cos(x)sin(x)

onegirl
 one year ago
Best ResponseYou've already chosen the best response.0@genius12 so the derivative of 2cos(x) sin(x) , and i got 2 cos(2x)

onegirl
 one year ago
Best ResponseYou've already chosen the best response.0@jazy should i now take the derivative of 2 cos(2x) ? or

RadEn
 one year ago
Best ResponseYou've already chosen the best response.0which one : dw:1362427439289:dw

RadEn
 one year ago
Best ResponseYou've already chosen the best response.0so, the first one in my diagram ?

RadEn
 one year ago
Best ResponseYou've already chosen the best response.0oke, to get the first derivative of f(x) we can use the cain rule hint : derivative of x^2 = 2x derivative of cos =  sin

onegirl
 one year ago
Best ResponseYou've already chosen the best response.0yea i got it the first derivative will be 2 cos(x) sin (x) right?

RadEn
 one year ago
Best ResponseYou've already chosen the best response.0so, derivative of f(x) = cosx^2 > f ' (x) = 2x(sinx^2) = 2x sinx^2

onegirl
 one year ago
Best ResponseYou've already chosen the best response.0so then i take the derivative of 2x sinx^2 ?

onegirl
 one year ago
Best ResponseYou've already chosen the best response.0okay after i take the derivative of 2x sinx i get 2 cos(2x) so then i take the derivative of 2 cos(2x) right?

RadEn
 one year ago
Best ResponseYou've already chosen the best response.0use the product rule to get the 2nd derivative : use the formula : f '' = u'v + uv' assuming that u=2x > u' = ... ? v = sinx^2 > v ' = ... ?

RadEn
 one year ago
Best ResponseYou've already chosen the best response.0do u know derivative of 2x ?

RadEn
 one year ago
Best ResponseYou've already chosen the best response.0yes, that's right also, sinx^2 ?

onegirl
 one year ago
Best ResponseYou've already chosen the best response.0but where does sinx^2 come from i got 2 cos(x) sin(x) ??

onegirl
 one year ago
Best ResponseYou've already chosen the best response.0for my derivative of cosx^2

RadEn
 one year ago
Best ResponseYou've already chosen the best response.0f(x) = cosx^2 > f ' (x) = 2x(sinx^2) = 2x sinx^2

RadEn
 one year ago
Best ResponseYou've already chosen the best response.0it just the first derivative of f(x), now we have to deriv again to get f " then, use the product rule

onegirl
 one year ago
Best ResponseYou've already chosen the best response.0so now i need to find the derivative of sin^x right? since we found 2x which we got 2

onegirl
 one year ago
Best ResponseYou've already chosen the best response.0and i got cos (x) sin(x)

onegirl
 one year ago
Best ResponseYou've already chosen the best response.0so it will be 2 cos(x) sin(x) right?

RadEn
 one year ago
Best ResponseYou've already chosen the best response.02x sinx^2 let u=2x > u' = 2 v = sinx^2 > v ' = 2xcoscx^2

RadEn
 one year ago
Best ResponseYou've already chosen the best response.0sorry, it should v' = 2xcosx^2

onegirl
 one year ago
Best ResponseYou've already chosen the best response.0okay so how would i set it up in the formula ?

RadEn
 one year ago
Best ResponseYou've already chosen the best response.0f " = u'v + uv' f " = (2)sinx^2 + (2x)2xcosx^2 = 2sinx^2  4x^2cosx^2

onegirl
 one year ago
Best ResponseYou've already chosen the best response.0okay so the f'''(x) will be 2sinx^2 = 4x^2 cosx^2 ?

onegirl
 one year ago
Best ResponseYou've already chosen the best response.0@RadEn so thats the final answer?
Ask your own question
Ask a QuestionFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.