mikaa_toxica13
Choose the correct simplification of the expression (3xy^4)^2(y^2)^3.
6x^2y^14
9x^2y^14
9x^3y^11
6x^3y^11



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mikaa_toxica13
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medal and fan to best answer/explaination

anonymous
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since \(3^2=9\) you can forget 1 and 4

mikaa_toxica13
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im thinkin its 2

anonymous
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\[ (3xy^4)^2(y^2)^3\] square everything first, i.e. multiply all the exponents by 2

gabrielle12
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9x^2y^11

gabrielle12
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you distribute the exponents outside of the parentheses to all the terms inside the parentheses

anonymous
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then
\[3^2x^4y^8\times y^6\] now add up the exponents

anonymous
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you get
\[9x^2y^{14}\]

anonymous
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oops i made a mistake above, there is no \(x^4\) term it is \(x^2\)

anonymous
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you are right, it is 2

mikaa_toxica13
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thanks !!