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mathcalculus
 2 years ago
For the following function, h , determine the functions, f and g so that : h(x)= f(g(x))
If
h(x)=(8x+8/11x11)^7
then
f(x)
g(x)
mathcalculus
 2 years ago
For the following function, h , determine the functions, f and g so that : h(x)= f(g(x)) If h(x)=(8x+8/11x11)^7 then f(x) g(x)

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kirbykirby
 2 years ago
Best ResponseYou've already chosen the best response.1Do you still need help even though your question is closed

kirbykirby
 2 years ago
Best ResponseYou've already chosen the best response.1Ok well for compositions, you have to imagine a function being INSIDE another function

kirbykirby
 2 years ago
Best ResponseYou've already chosen the best response.1The basic functions are like: \(ln(x), cos(x), sin(x), x, e^x...\) ... so if you have like \(x^2dw:1362456641846:dw\)

kirbykirby
 2 years ago
Best ResponseYou've already chosen the best response.1In your case we have dw:1362456844212:dw

kirbykirby
 2 years ago
Best ResponseYou've already chosen the best response.1so, in math we'd say \(f(g(x))=h(x)\), so we let the inner function (the square box) be g(x)... since it's inside of f... \(g(x)=\frac{8x+8}{11x11}\) Now you want to make all of g(x) to be raised to the power of 7. What we typically do is let \(u=g(x)\), now define \(f(u)=u^7\) dw:1362457135131:dw

kirbykirby
 2 years ago
Best ResponseYou've already chosen the best response.1Ok no offense though but can you not see I'm still writing ? You know this openstudy site is voluntary for those to post answers, it's kind of rude to rush people with "?????????"

mathcalculus
 2 years ago
Best ResponseYou've already chosen the best response.0don't waste my time if you're going to get emotional. & exactly, voluntarily. voluntarily leave.

kirbykirby
 2 years ago
Best ResponseYou've already chosen the best response.1Well how am I wasting your time if I just posted the solution for you. And I am not wasting your time becuse it takes time to draw these pictures and code using LaTex

mathcalculus
 2 years ago
Best ResponseYou've already chosen the best response.0lol just reading you reply is a waste. don't bother replying.

mathcalculus
 2 years ago
Best ResponseYou've already chosen the best response.0thanks but no thanks! :)

kirbykirby
 2 years ago
Best ResponseYou've already chosen the best response.1Wow I can't believe how ungrateful you are. You are even lucky there are people willing to voluntarily help you with your homework

mathcalculus
 2 years ago
Best ResponseYou've already chosen the best response.0omg, enough. thanks kirby!

mathcalculus
 2 years ago
Best ResponseYou've already chosen the best response.0i just saved you some trouble.

mathcalculus
 2 years ago
Best ResponseYou've already chosen the best response.0I did not intend to be rude.. I just had a bad day, so please don't let it ruin yours, sincerely me.
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