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For the following function, h , determine the functions, f and g so that : h(x)= f(g(x))
If
h(x)=(8x+8/11x11)^7
then
f(x)
g(x)
 one year ago
 one year ago
For the following function, h , determine the functions, f and g so that : h(x)= f(g(x)) If h(x)=(8x+8/11x11)^7 then f(x) g(x)
 one year ago
 one year ago

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kirbykirbyBest ResponseYou've already chosen the best response.1
Do you still need help even though your question is closed
 one year ago

kirbykirbyBest ResponseYou've already chosen the best response.1
Ok well for compositions, you have to imagine a function being INSIDE another function
 one year ago

kirbykirbyBest ResponseYou've already chosen the best response.1
The basic functions are like: \(ln(x), cos(x), sin(x), x, e^x...\) ... so if you have like \(x^2dw:1362456641846:dw\)
 one year ago

kirbykirbyBest ResponseYou've already chosen the best response.1
In your case we have dw:1362456844212:dw
 one year ago

kirbykirbyBest ResponseYou've already chosen the best response.1
so, in math we'd say \(f(g(x))=h(x)\), so we let the inner function (the square box) be g(x)... since it's inside of f... \(g(x)=\frac{8x+8}{11x11}\) Now you want to make all of g(x) to be raised to the power of 7. What we typically do is let \(u=g(x)\), now define \(f(u)=u^7\) dw:1362457135131:dw
 one year ago

kirbykirbyBest ResponseYou've already chosen the best response.1
Ok no offense though but can you not see I'm still writing ? You know this openstudy site is voluntary for those to post answers, it's kind of rude to rush people with "?????????"
 one year ago

mathcalculusBest ResponseYou've already chosen the best response.0
don't waste my time if you're going to get emotional. & exactly, voluntarily. voluntarily leave.
 one year ago

kirbykirbyBest ResponseYou've already chosen the best response.1
Well how am I wasting your time if I just posted the solution for you. And I am not wasting your time becuse it takes time to draw these pictures and code using LaTex
 one year ago

mathcalculusBest ResponseYou've already chosen the best response.0
lol just reading you reply is a waste. don't bother replying.
 one year ago

mathcalculusBest ResponseYou've already chosen the best response.0
thanks but no thanks! :)
 one year ago

kirbykirbyBest ResponseYou've already chosen the best response.1
Wow I can't believe how ungrateful you are. You are even lucky there are people willing to voluntarily help you with your homework
 one year ago

mathcalculusBest ResponseYou've already chosen the best response.0
omg, enough. thanks kirby!
 one year ago

mathcalculusBest ResponseYou've already chosen the best response.0
i just saved you some trouble.
 one year ago

mathcalculusBest ResponseYou've already chosen the best response.0
I did not intend to be rude.. I just had a bad day, so please don't let it ruin yours, sincerely me.
 one year ago
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