anonymous
  • anonymous
For the following function, h , determine the functions, f and g so that : h(x)= f(g(x)) If h(x)=(8x+8/11x-11)^7 then f(x) g(x)
Calculus1
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
helppppp :(
kirbykirby
  • kirbykirby
Do you still need help even though your question is closed
anonymous
  • anonymous
yes please

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kirbykirby
  • kirbykirby
Ok well for compositions, you have to imagine a function being INSIDE another function
kirbykirby
  • kirbykirby
The basic functions are like: \(ln(x), cos(x), sin(x), x, e^x...\) ... so if you have like \(x^2|dw:1362456641846:dw|\)
kirbykirby
  • kirbykirby
In your case we have |dw:1362456844212:dw|
anonymous
  • anonymous
yeah
anonymous
  • anonymous
then?
anonymous
  • anonymous
?????
kirbykirby
  • kirbykirby
so, in math we'd say \(f(g(x))=h(x)\), so we let the inner function (the square box) be g(x)... since it's inside of f... \(g(x)=\frac{8x+8}{11x-11}\) Now you want to make all of g(x) to be raised to the power of 7. What we typically do is let \(u=g(x)\), now define \(f(u)=u^7\) |dw:1362457135131:dw|
kirbykirby
  • kirbykirby
Ok no offense though but can you not see I'm still writing ? You know this openstudy site is voluntary for those to post answers, it's kind of rude to rush people with "?????????"
anonymous
  • anonymous
don't waste my time if you're going to get emotional. & exactly, voluntarily. voluntarily leave.
kirbykirby
  • kirbykirby
Well how am I wasting your time if I just posted the solution for you. And I am not wasting your time becuse it takes time to draw these pictures and code using LaTex
anonymous
  • anonymous
lol just reading you reply is a waste. don't bother replying.
anonymous
  • anonymous
thanks but no thanks! :)
kirbykirby
  • kirbykirby
Wow I can't believe how ungrateful you are. You are even lucky there are people willing to voluntarily help you with your homework
anonymous
  • anonymous
omg, enough. thanks kirby!
anonymous
  • anonymous
i just saved you some trouble.
anonymous
  • anonymous
I did not intend to be rude.. I just had a bad day, so please don't let it ruin yours, sincerely me.

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