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 one year ago
For the following function, h , determine the functions, f and g so that : h(x)= f(g(x))
If
h(x)=(8x+8/11x11)^7
then
f(x)
g(x)
 one year ago
For the following function, h , determine the functions, f and g so that : h(x)= f(g(x)) If h(x)=(8x+8/11x11)^7 then f(x) g(x)

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kirbykirby
 one year ago
Best ResponseYou've already chosen the best response.1Do you still need help even though your question is closed

kirbykirby
 one year ago
Best ResponseYou've already chosen the best response.1Ok well for compositions, you have to imagine a function being INSIDE another function

kirbykirby
 one year ago
Best ResponseYou've already chosen the best response.1The basic functions are like: \(ln(x), cos(x), sin(x), x, e^x...\) ... so if you have like \(x^2dw:1362456641846:dw\)

kirbykirby
 one year ago
Best ResponseYou've already chosen the best response.1In your case we have dw:1362456844212:dw

kirbykirby
 one year ago
Best ResponseYou've already chosen the best response.1so, in math we'd say \(f(g(x))=h(x)\), so we let the inner function (the square box) be g(x)... since it's inside of f... \(g(x)=\frac{8x+8}{11x11}\) Now you want to make all of g(x) to be raised to the power of 7. What we typically do is let \(u=g(x)\), now define \(f(u)=u^7\) dw:1362457135131:dw

kirbykirby
 one year ago
Best ResponseYou've already chosen the best response.1Ok no offense though but can you not see I'm still writing ? You know this openstudy site is voluntary for those to post answers, it's kind of rude to rush people with "?????????"

mathcalculus
 one year ago
Best ResponseYou've already chosen the best response.0don't waste my time if you're going to get emotional. & exactly, voluntarily. voluntarily leave.

kirbykirby
 one year ago
Best ResponseYou've already chosen the best response.1Well how am I wasting your time if I just posted the solution for you. And I am not wasting your time becuse it takes time to draw these pictures and code using LaTex

mathcalculus
 one year ago
Best ResponseYou've already chosen the best response.0lol just reading you reply is a waste. don't bother replying.

mathcalculus
 one year ago
Best ResponseYou've already chosen the best response.0thanks but no thanks! :)

kirbykirby
 one year ago
Best ResponseYou've already chosen the best response.1Wow I can't believe how ungrateful you are. You are even lucky there are people willing to voluntarily help you with your homework

mathcalculus
 one year ago
Best ResponseYou've already chosen the best response.0omg, enough. thanks kirby!

mathcalculus
 one year ago
Best ResponseYou've already chosen the best response.0i just saved you some trouble.

mathcalculus
 one year ago
Best ResponseYou've already chosen the best response.0I did not intend to be rude.. I just had a bad day, so please don't let it ruin yours, sincerely me.
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