anonymous
  • anonymous
Helppppppp :( For the following function, h , determine the functions, f and g so that : h(x)= f(g(x)) If h(x)=(8x+8/11x-11)^7 then f(x) g(x)
Calculus1
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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Mertsj
  • Mertsj
f(x)=x^7 g(x)=(8x+8)/(11x-11)
anonymous
  • anonymous
so then do i plug in the equation in x^7?
Mertsj
  • Mertsj
I thought the problem asked you what the functions f and g are

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anonymous
  • anonymous
yup
anonymous
  • anonymous
can you show me what the next steps are? i'm a bit confused..
Mertsj
  • Mertsj
The problem told you that the f(g(x))=
anonymous
  • anonymous
steps
anonymous
  • anonymous
i know what the problem said but can you show me?
Mertsj
  • Mertsj
\[(\frac{8x+8}{11x-11})^7\]
anonymous
  • anonymous
okay.. i did that
Mertsj
  • Mertsj
Then it asked you what the f(x) is and what the g(x) is. So can you see that the f(x)=x^7 and you replace x with (8x+8)/(11x-11) that you will get the f(g(x))? There is really no work to show. It's just to demonstrate your understanding of function composition.
anonymous
  • anonymous
there is work to show
anonymous
  • anonymous
how can they give us a problem without any work???
Mertsj
  • Mertsj
Supposing they ask you what 4 x 3 is. Would there be work to show?
anonymous
  • anonymous
after you found f(x)= x^7 when you plug in 8X+8etc etc.... what is the number or answer from there?
Mertsj
  • Mertsj
I'm thinking you don't know what the problem is asking.
anonymous
  • anonymous
of course I can. I can show 4 columns and 3 rows of apples to equal to 12!
anonymous
  • anonymous
i do. I submitted the "answer" of not showing the work.... hint hint wrong
anonymous
  • anonymous
there is work. its math buddy
Mertsj
  • Mertsj
The problem says if h(x)= ... Then f(x)= and you should write x^7 g(x)= and you should write (8x+8)/(11x-11)
anonymous
  • anonymous
yes i did
Mertsj
  • Mertsj
And?
Mertsj
  • Mertsj
@satellite73 Maybe satellite can help you with your work. He's really smart.
anonymous
  • anonymous
I see...
anonymous
  • anonymous
thanks so much :)
Mertsj
  • Mertsj
yw. sorry
anonymous
  • anonymous
lol no worries, again thank you.

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