Ace school

with brainly

  • Get help from millions of students
  • Learn from experts with step-by-step explanations
  • Level-up by helping others

A community for students.

HELP! who can explain derivatives :( let f(x)= (x^3+3x+8)^2 F'(x)= F'(2)=

Calculus1
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get this expert

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this and thousands of other questions

use the chain rule get \[F'(x)=2(x^2+3x+8)(3x^2+3)\]
I am very bad with derivatives. I missed the whole lesson de to being sick. can we start from the beginning?
how do we use the chain rule?

Not the answer you are looking for?

Search for more explanations.

Ask your own question

Other answers:

you have something squared the derivative of something squared is two times something, times the derivative of something
for example, the derivative of \(\sin^2(x)\) is \(2\sin(x)\cos(x)\)
the derivative of \(x+\sqrt{x}+\tan(x))^2\) is \[2(x+\sqrt{x}+\tan(x))(1+\frac{1}{2\sqrt{x}}+\sec^2(x))\]
okay
so how do we begin this problem?
to find the derivative we need to place the exponent in front... correct?
is the derivative for f'(x) = 2X^2+6X+16?

Not the answer you are looking for?

Search for more explanations.

Ask your own question