## anonymous 3 years ago HELP! who can explain derivatives :( let f(x)= (x^3+3x+8)^2 F'(x)= F'(2)=

1. anonymous

use the chain rule get $F'(x)=2(x^2+3x+8)(3x^2+3)$

2. anonymous

I am very bad with derivatives. I missed the whole lesson de to being sick. can we start from the beginning?

3. anonymous

how do we use the chain rule?

4. anonymous

you have something squared the derivative of something squared is two times something, times the derivative of something

5. anonymous

for example, the derivative of $$\sin^2(x)$$ is $$2\sin(x)\cos(x)$$

6. anonymous

the derivative of $$x+\sqrt{x}+\tan(x))^2$$ is $2(x+\sqrt{x}+\tan(x))(1+\frac{1}{2\sqrt{x}}+\sec^2(x))$

7. anonymous

okay

8. anonymous

so how do we begin this problem?

9. anonymous

to find the derivative we need to place the exponent in front... correct?

10. anonymous

is the derivative for f'(x) = 2X^2+6X+16?