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anonymous
 3 years ago
HELP! who can explain derivatives :(
let f(x)= (x^3+3x+8)^2
F'(x)=
F'(2)=
anonymous
 3 years ago
HELP! who can explain derivatives :( let f(x)= (x^3+3x+8)^2 F'(x)= F'(2)=

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anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0use the chain rule get \[F'(x)=2(x^2+3x+8)(3x^2+3)\]

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0I am very bad with derivatives. I missed the whole lesson de to being sick. can we start from the beginning?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0how do we use the chain rule?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0you have something squared the derivative of something squared is two times something, times the derivative of something

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0for example, the derivative of \(\sin^2(x)\) is \(2\sin(x)\cos(x)\)

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0the derivative of \(x+\sqrt{x}+\tan(x))^2\) is \[2(x+\sqrt{x}+\tan(x))(1+\frac{1}{2\sqrt{x}}+\sec^2(x))\]

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0so how do we begin this problem?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0to find the derivative we need to place the exponent in front... correct?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0is the derivative for f'(x) = 2X^2+6X+16?
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