## mathcalculus 2 years ago HELP! who can explain derivatives :( let f(x)= (x^3+3x+8)^2 F'(x)= F'(2)=

1. satellite73

use the chain rule get $F'(x)=2(x^2+3x+8)(3x^2+3)$

2. mathcalculus

I am very bad with derivatives. I missed the whole lesson de to being sick. can we start from the beginning?

3. mathcalculus

how do we use the chain rule?

4. satellite73

you have something squared the derivative of something squared is two times something, times the derivative of something

5. satellite73

for example, the derivative of $$\sin^2(x)$$ is $$2\sin(x)\cos(x)$$

6. satellite73

the derivative of $$x+\sqrt{x}+\tan(x))^2$$ is $2(x+\sqrt{x}+\tan(x))(1+\frac{1}{2\sqrt{x}}+\sec^2(x))$

7. mathcalculus

okay

8. mathcalculus

so how do we begin this problem?

9. mathcalculus

to find the derivative we need to place the exponent in front... correct?

10. mathcalculus

is the derivative for f'(x) = 2X^2+6X+16?