## mathcalculus Group Title HELP! who can explain derivatives :( let f(x)= (x^3+3x+8)^2 F'(x)= F'(2)= one year ago one year ago

1. satellite73 Group Title

use the chain rule get $F'(x)=2(x^2+3x+8)(3x^2+3)$

2. mathcalculus Group Title

I am very bad with derivatives. I missed the whole lesson de to being sick. can we start from the beginning?

3. mathcalculus Group Title

how do we use the chain rule?

4. satellite73 Group Title

you have something squared the derivative of something squared is two times something, times the derivative of something

5. satellite73 Group Title

for example, the derivative of $$\sin^2(x)$$ is $$2\sin(x)\cos(x)$$

6. satellite73 Group Title

the derivative of $$x+\sqrt{x}+\tan(x))^2$$ is $2(x+\sqrt{x}+\tan(x))(1+\frac{1}{2\sqrt{x}}+\sec^2(x))$

7. mathcalculus Group Title

okay

8. mathcalculus Group Title

so how do we begin this problem?

9. mathcalculus Group Title

to find the derivative we need to place the exponent in front... correct?

10. mathcalculus Group Title

is the derivative for f'(x) = 2X^2+6X+16?