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Yasminelove1
Group Title
What is the approximate perimeter of the composite figure shown? Use three point one four for pi.
 one year ago
 one year ago
Yasminelove1 Group Title
What is the approximate perimeter of the composite figure shown? Use three point one four for pi.
 one year ago
 one year ago

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ash2326 Group TitleBest ResponseYou've already chosen the best response.2
Can you find the area of right triangle with base 5 mi and height 5 mi?
 one year ago

ash2326 Group TitleBest ResponseYou've already chosen the best response.2
Do you know the formula for area of right triangle and\or circle?
 one year ago

Yasminelove1 Group TitleBest ResponseYou've already chosen the best response.1
A=1/2xbxh or A=bxh/2
 one year ago

Yasminelove1 Group TitleBest ResponseYou've already chosen the best response.1
Circle Area = π × r2 Circumference = 2 × π × r r = radius
 one year ago

ash2326 Group TitleBest ResponseYou've already chosen the best response.2
Good, you're right here for the triangle b=5 mi h=5 mi \[\frac 1 2 b\times h\] Just plugin the values, you'll get the area of triangle
 one year ago

Yasminelove1 Group TitleBest ResponseYou've already chosen the best response.1
wat do you mean by that
 one year ago

ash2326 Group TitleBest ResponseYou've already chosen the best response.2
put b=5 and h=5, then solve it to find the area of triangle
 one year ago

Yasminelove1 Group TitleBest ResponseYou've already chosen the best response.1
so ur saying 5x5x3.14
 one year ago

ash2326 Group TitleBest ResponseYou've already chosen the best response.2
Nope, \[\text{Area of figure}=\text{Area of triangle+ Area of circle}\] \[\text{Area of triangle}=\frac 1 2 \times 5 \times 5\ mi^2\]
 one year ago

Yasminelove1 Group TitleBest ResponseYou've already chosen the best response.1
oh ok i get 12 1/2 tho
 one year ago

ash2326 Group TitleBest ResponseYou've already chosen the best response.2
Yes, you're right. Now we need to find the area of semi circle, It's diameter is 7 mi Can you find the area?
 one year ago

Yasminelove1 Group TitleBest ResponseYou've already chosen the best response.1
A semicircle is half of a circle and the area of a circle of radius r is pi r2. We know that the area of a circle is: area of a circle = pi r2 A semicircle is half of a circle. Therefore the area of a semicircle will be: area of a semicircle = 1/2 pi r2 We know that the radius is 9ft. Pi is approximately 3.14 or 22/7. Now you just have to plug in the numbers and you will find the area!
 one year ago

ash2326 Group TitleBest ResponseYou've already chosen the best response.2
What's the radius here?
 one year ago

Yasminelove1 Group TitleBest ResponseYou've already chosen the best response.1
First, let's look at the 2 dimensional region (base of solid) Each crosssection perpendicular to the xaxis is a "strip" of length e^x  0 = e^x Now we can look at 3 dimensional solid Each crosssection perpendicular to the xaxis is a semicircle with diameter = e^x So each crosssection has area = 1/2 (π r²) = 1/2 π (e^x/2)² = π/8 * e^(2x) Each very thin cross section of width dx has volume = π/8 * e^(2x) dx Integrating from x = 1 to x = 1, we get: Volume = ∫₋₁¹ π/8 * e^(2x) dx . . . . . . = π/16 * e^(2x) ₋₁¹ . . . . . . = π/16 (e^(2)  e^(2)) . . . . . . = 1.4242647516
 one year ago

ash2326 Group TitleBest ResponseYou've already chosen the best response.2
From where are you posting this??? It's not relevant here
 one year ago

amistre64 Group TitleBest ResponseYou've already chosen the best response.0
@preetha we need to get shadow to clean up the database .....
 one year ago

amistre64 Group TitleBest ResponseYou've already chosen the best response.0
@shadowfiend might need your assistance in cleaning up some database material
 one year ago

amistre64 Group TitleBest ResponseYou've already chosen the best response.0
please check the users profile page for some rather inappropriate content.
 one year ago

amistre64 Group TitleBest ResponseYou've already chosen the best response.0
they also seem to have a habit of editing the content out of their questions :/
 one year ago
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