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mikaa_toxica13

  • 3 years ago

Choose the correct simplification of the expression 9 over h^-3. h^3 over 9 9 over h^3 9h^3 This expression is already simplified. @mathstudent55 can u help ?

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  1. MATTW20
    • 3 years ago
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    c

  2. mikaa_toxica13
    • 3 years ago
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    explain @MATTW20

  3. MATTW20
    • 3 years ago
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    if you have an expression with a negative exponent that is in the bottom portion of the fraction. putting it in the top of the fraction makes it positive.

  4. NickR
    • 3 years ago
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    1/exponent is the same as -exponent/1

  5. mikaa_toxica13
    • 3 years ago
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    cann u help with a few others ? its short

  6. MATTW20
    • 3 years ago
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    sure

  7. mikaa_toxica13
    • 3 years ago
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    Choose the correct simplification of the expression (2b over c)^3. 2b^3 over c^3 8b^3 over c^3 2b^3 over c 2b over c^3

  8. MATTW20
    • 3 years ago
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    a

  9. MATTW20
    • 3 years ago
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    both expressions get raised to the third power because they're in parentheses

  10. mikaa_toxica13
    • 3 years ago
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    Choose the correct simplification of the expression g^5 h^4 over g ^2 h^3. g^7h g^3h g^7h^7 g^3 over h^7

  11. MATTW20
    • 3 years ago
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    b. When you have variables with exponents over variables with exponents you subtract the exponents

  12. mikaa_toxica13
    • 3 years ago
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    @MATTW20 last one i promise ! Show the expanded form and simplification of x^6 over x^2. Explain in your own words how you can simplify x^6 over x^2 without having to write the expanded form. Create your own fraction with like bases, coefficients, and show its simplification

  13. MATTW20
    • 3 years ago
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    |dw:1362510116798:dw|

  14. MATTW20
    • 3 years ago
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    you can simplify (x^6)/(x^2) without writing expanded form by using the formula \[\frac{ x ^{a} }{ x ^{b} }=x ^{a-b}\] so \[\frac{ x ^{6} }{ x ^{2} }=x ^{6-2}=x ^{4}\]

  15. mikaa_toxica13
    • 3 years ago
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    thank u !!!!!

  16. MATTW20
    • 3 years ago
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    As for the last one all you have to do is make up a problem of your own and solve it

  17. mikaa_toxica13
    • 3 years ago
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    thats the part im not good at

  18. MATTW20
    • 3 years ago
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    why?

  19. MATTW20
    • 3 years ago
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    you can make it as easy or difficult as you like

  20. mikaa_toxica13
    • 3 years ago
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    yeaa but i have no clue aout this. so i would know how to even make an equation or solve it :/

  21. MATTW20
    • 3 years ago
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    just put some in the form of \[\frac{ x ^{a} }{ x ^{b} }\] a and b can be whatever number you like

  22. MATTW20
    • 3 years ago
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    just make them different numbers

  23. MATTW20
    • 3 years ago
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    @mikaa_toxica13

  24. mikaa_toxica13
    • 3 years ago
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    sory. i was preoccupied. u know with what lol. something like x^5 over x^7 ?

  25. mikaa_toxica13
    • 3 years ago
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    @MATTW20

  26. MATTW20
    • 3 years ago
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    okay so now you use the formula i showed you earlier \[\frac{ x ^{a} }{ x ^{b} }=x ^{a-b}\] just substitute a for 5 and b for 7

  27. mikaa_toxica13
    • 3 years ago
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    so it would be x^5 --- = x^5-7 x^7

  28. MATTW20
    • 3 years ago
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    which is \[x ^{-2}\]

  29. MATTW20
    • 3 years ago
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    but what if we wanted the exponent to be positive?

  30. mikaa_toxica13
    • 3 years ago
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    oh i thought it was supposed to be like 5 minus 7

  31. MATTW20
    • 3 years ago
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    well what is 5-7?

  32. mikaa_toxica13
    • 3 years ago
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    idk btw the second answer u gave me was wrong.

  33. MATTW20
    • 3 years ago
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    sorry about that It's been a while since taking algebra. The answer is right but idk what you're instructor was looking for in the explanation.

  34. MATTW20
    • 3 years ago
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    anyway the answer would be \[x ^{-2}\] or if you like \[\frac{ 1 }{ x ^{2} }\]

  35. MATTW20
    • 3 years ago
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    oh the 2nd overall answer. My fault i completely apologize. It would've been b.

  36. MATTW20
    • 3 years ago
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    anyway good luck sorry about the mistake. I'm here to help if you need it

  37. mikaa_toxica13
    • 3 years ago
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    i got it thanks maybe u should recheck your math

  38. MATTW20
    • 3 years ago
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    yes ma'am

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