mikaa_toxica13
Choose the correct simplification of the expression 9 over h^-3.
h^3 over 9
9 over h^3
9h^3
This expression is already simplified.
@mathstudent55 can u help ?
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MATTW20
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c
mikaa_toxica13
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explain @MATTW20
MATTW20
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if you have an expression with a negative exponent that is in the bottom portion of the fraction. putting it in the top of the fraction makes it positive.
NickR
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1/exponent is the same as -exponent/1
mikaa_toxica13
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cann u help with a few others ? its short
MATTW20
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sure
mikaa_toxica13
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Choose the correct simplification of the expression (2b over c)^3.
2b^3 over c^3
8b^3 over c^3
2b^3 over c
2b over c^3
MATTW20
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a
MATTW20
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both expressions get raised to the third power because they're in parentheses
mikaa_toxica13
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Choose the correct simplification of the expression g^5 h^4 over g ^2 h^3.
g^7h
g^3h
g^7h^7
g^3 over h^7
MATTW20
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b. When you have variables with exponents over variables with exponents you subtract the exponents
mikaa_toxica13
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@MATTW20 last one i promise !
Show the expanded form and simplification of x^6 over x^2. Explain in your own words how you can simplify x^6 over x^2 without having to write the expanded form.
Create your own fraction with like bases, coefficients, and show its simplification
MATTW20
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|dw:1362510116798:dw|
MATTW20
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you can simplify (x^6)/(x^2) without writing expanded form by using the formula \[\frac{ x ^{a} }{ x ^{b} }=x ^{a-b}\]
so \[\frac{ x ^{6} }{ x ^{2} }=x ^{6-2}=x ^{4}\]
mikaa_toxica13
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thank u !!!!!
MATTW20
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As for the last one all you have to do is make up a problem of your own and solve it
mikaa_toxica13
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thats the part im not good at
MATTW20
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why?
MATTW20
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you can make it as easy or difficult as you like
mikaa_toxica13
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yeaa but i have no clue aout this. so i would know how to even make an equation or solve it :/
MATTW20
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just put some in the form of \[\frac{ x ^{a} }{ x ^{b} }\] a and b can be whatever number you like
MATTW20
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just make them different numbers
MATTW20
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@mikaa_toxica13
mikaa_toxica13
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sory. i was preoccupied. u know with what lol. something like x^5 over x^7 ?
mikaa_toxica13
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@MATTW20
MATTW20
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okay so now you use the formula i showed you earlier \[\frac{ x ^{a} }{ x ^{b} }=x ^{a-b}\] just substitute a for 5 and b for 7
mikaa_toxica13
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so it would be
x^5
--- = x^5-7
x^7
MATTW20
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which is \[x ^{-2}\]
MATTW20
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but what if we wanted the exponent to be positive?
mikaa_toxica13
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oh i thought it was supposed to be like 5 minus 7
MATTW20
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well what is 5-7?
mikaa_toxica13
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idk btw the second answer u gave me was wrong.
MATTW20
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sorry about that It's been a while since taking algebra. The answer is right but idk what you're instructor was looking for in the explanation.
MATTW20
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anyway the answer would be \[x ^{-2}\] or if you like \[\frac{ 1 }{ x ^{2} }\]
MATTW20
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oh the 2nd overall answer. My fault i completely apologize. It would've been b.
MATTW20
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anyway good luck sorry about the mistake. I'm here to help if you need it
mikaa_toxica13
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i got it thanks maybe u should recheck your math
MATTW20
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yes ma'am