anonymous
  • anonymous
Choose the correct simplification of the expression 9 over h^-3. h^3 over 9 9 over h^3 9h^3 This expression is already simplified. @mathstudent55 can u help ?
Mathematics
schrodinger
  • schrodinger
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anonymous
  • anonymous
c
anonymous
  • anonymous
explain @MATTW20
anonymous
  • anonymous
if you have an expression with a negative exponent that is in the bottom portion of the fraction. putting it in the top of the fraction makes it positive.

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anonymous
  • anonymous
1/exponent is the same as -exponent/1
anonymous
  • anonymous
cann u help with a few others ? its short
anonymous
  • anonymous
sure
anonymous
  • anonymous
Choose the correct simplification of the expression (2b over c)^3. 2b^3 over c^3 8b^3 over c^3 2b^3 over c 2b over c^3
anonymous
  • anonymous
a
anonymous
  • anonymous
both expressions get raised to the third power because they're in parentheses
anonymous
  • anonymous
Choose the correct simplification of the expression g^5 h^4 over g ^2 h^3. g^7h g^3h g^7h^7 g^3 over h^7
anonymous
  • anonymous
b. When you have variables with exponents over variables with exponents you subtract the exponents
anonymous
  • anonymous
@MATTW20 last one i promise ! Show the expanded form and simplification of x^6 over x^2. Explain in your own words how you can simplify x^6 over x^2 without having to write the expanded form. Create your own fraction with like bases, coefficients, and show its simplification
anonymous
  • anonymous
|dw:1362510116798:dw|
anonymous
  • anonymous
you can simplify (x^6)/(x^2) without writing expanded form by using the formula \[\frac{ x ^{a} }{ x ^{b} }=x ^{a-b}\] so \[\frac{ x ^{6} }{ x ^{2} }=x ^{6-2}=x ^{4}\]
anonymous
  • anonymous
thank u !!!!!
anonymous
  • anonymous
As for the last one all you have to do is make up a problem of your own and solve it
anonymous
  • anonymous
thats the part im not good at
anonymous
  • anonymous
why?
anonymous
  • anonymous
you can make it as easy or difficult as you like
anonymous
  • anonymous
yeaa but i have no clue aout this. so i would know how to even make an equation or solve it :/
anonymous
  • anonymous
just put some in the form of \[\frac{ x ^{a} }{ x ^{b} }\] a and b can be whatever number you like
anonymous
  • anonymous
just make them different numbers
anonymous
  • anonymous
anonymous
  • anonymous
sory. i was preoccupied. u know with what lol. something like x^5 over x^7 ?
anonymous
  • anonymous
anonymous
  • anonymous
okay so now you use the formula i showed you earlier \[\frac{ x ^{a} }{ x ^{b} }=x ^{a-b}\] just substitute a for 5 and b for 7
anonymous
  • anonymous
so it would be x^5 --- = x^5-7 x^7
anonymous
  • anonymous
which is \[x ^{-2}\]
anonymous
  • anonymous
but what if we wanted the exponent to be positive?
anonymous
  • anonymous
oh i thought it was supposed to be like 5 minus 7
anonymous
  • anonymous
well what is 5-7?
anonymous
  • anonymous
idk btw the second answer u gave me was wrong.
anonymous
  • anonymous
sorry about that It's been a while since taking algebra. The answer is right but idk what you're instructor was looking for in the explanation.
anonymous
  • anonymous
anyway the answer would be \[x ^{-2}\] or if you like \[\frac{ 1 }{ x ^{2} }\]
anonymous
  • anonymous
oh the 2nd overall answer. My fault i completely apologize. It would've been b.
anonymous
  • anonymous
anyway good luck sorry about the mistake. I'm here to help if you need it
anonymous
  • anonymous
i got it thanks maybe u should recheck your math
anonymous
  • anonymous
yes ma'am

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