Choose the correct simplification of the expression 9 over h^-3.
h^3 over 9
9 over h^3
9h^3
This expression is already simplified.
@mathstudent55 can u help ?

- anonymous

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- anonymous

c

- anonymous

explain @MATTW20

- anonymous

if you have an expression with a negative exponent that is in the bottom portion of the fraction. putting it in the top of the fraction makes it positive.

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## More answers

- anonymous

1/exponent is the same as -exponent/1

- anonymous

cann u help with a few others ? its short

- anonymous

sure

- anonymous

Choose the correct simplification of the expression (2b over c)^3.
2b^3 over c^3
8b^3 over c^3
2b^3 over c
2b over c^3

- anonymous

a

- anonymous

both expressions get raised to the third power because they're in parentheses

- anonymous

Choose the correct simplification of the expression g^5 h^4 over g ^2 h^3.
g^7h
g^3h
g^7h^7
g^3 over h^7

- anonymous

b. When you have variables with exponents over variables with exponents you subtract the exponents

- anonymous

@MATTW20 last one i promise !
Show the expanded form and simplification of x^6 over x^2. Explain in your own words how you can simplify x^6 over x^2 without having to write the expanded form.
Create your own fraction with like bases, coefficients, and show its simplification

- anonymous

|dw:1362510116798:dw|

- anonymous

you can simplify (x^6)/(x^2) without writing expanded form by using the formula \[\frac{ x ^{a} }{ x ^{b} }=x ^{a-b}\]
so \[\frac{ x ^{6} }{ x ^{2} }=x ^{6-2}=x ^{4}\]

- anonymous

thank u !!!!!

- anonymous

As for the last one all you have to do is make up a problem of your own and solve it

- anonymous

thats the part im not good at

- anonymous

why?

- anonymous

you can make it as easy or difficult as you like

- anonymous

yeaa but i have no clue aout this. so i would know how to even make an equation or solve it :/

- anonymous

just put some in the form of \[\frac{ x ^{a} }{ x ^{b} }\] a and b can be whatever number you like

- anonymous

just make them different numbers

- anonymous

@mikaa_toxica13

- anonymous

sory. i was preoccupied. u know with what lol. something like x^5 over x^7 ?

- anonymous

@MATTW20

- anonymous

okay so now you use the formula i showed you earlier \[\frac{ x ^{a} }{ x ^{b} }=x ^{a-b}\] just substitute a for 5 and b for 7

- anonymous

so it would be
x^5
--- = x^5-7
x^7

- anonymous

which is \[x ^{-2}\]

- anonymous

but what if we wanted the exponent to be positive?

- anonymous

oh i thought it was supposed to be like 5 minus 7

- anonymous

well what is 5-7?

- anonymous

idk btw the second answer u gave me was wrong.

- anonymous

sorry about that It's been a while since taking algebra. The answer is right but idk what you're instructor was looking for in the explanation.

- anonymous

anyway the answer would be \[x ^{-2}\] or if you like \[\frac{ 1 }{ x ^{2} }\]

- anonymous

oh the 2nd overall answer. My fault i completely apologize. It would've been b.

- anonymous

anyway good luck sorry about the mistake. I'm here to help if you need it

- anonymous

i got it thanks maybe u should recheck your math

- anonymous

yes ma'am

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