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Can someone teach me how to solve an equation with variables on both sides? i need help :(
 one year ago
 one year ago
Can someone teach me how to solve an equation with variables on both sides? i need help :(
 one year ago
 one year ago

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LonelyandForgottenBest ResponseYou've already chosen the best response.1
yeah something like that
 one year ago

mykoBest ResponseYou've already chosen the best response.0
put all that have x one side and that have not , to the other
 one year ago

hisgirl2012Best ResponseYou've already chosen the best response.1
What is the equation you're trying to solve?
 one year ago

matineesuxxxBest ResponseYou've already chosen the best response.0
myko is right, but when you move a number to the other side of the eual sign you need to change the sign of the number itself. 4 becomes 4 and 4 becomes 4
 one year ago

LonelyandForgottenBest ResponseYou've already chosen the best response.1
well i understand that part but i cant go on further, i always get stuck :(
 one year ago

mykoBest ResponseYou've already chosen the best response.0
after you got something like this: ax=b do this: x=b/a andyou are done
 one year ago

matineesuxxxBest ResponseYou've already chosen the best response.0
so now how would you solve 4x=18?
 one year ago

LonelyandForgottenBest ResponseYou've already chosen the best response.1
dw:1362524358288:dw I dont know if this is right or wrong but i dont know where to go from there :/
 one year ago

LonelyandForgottenBest ResponseYou've already chosen the best response.1
that is the problem i am working on now
 one year ago

hisgirl2012Best ResponseYou've already chosen the best response.1
If you're getting the "X's" on one side then make sure you include the x. You're combining like terms. So it would be +3x under the 3x and the 7x. But you got it right so far after you get there your going to combine the +2 and the 22.
 one year ago

LonelyandForgottenBest ResponseYou've already chosen the best response.1
okay i can go on from there, thanks for your help :)
 one year ago

LonelyandForgottenBest ResponseYou've already chosen the best response.1
dw:1362525009117:dw Is this right?
 one year ago

LonelyandForgottenBest ResponseYou've already chosen the best response.1
can you help me please :(
 one year ago

ghaziBest ResponseYou've already chosen the best response.1
3x + 2 = 7x22 now bring like terms at one side so terms with variable lets say the ones with "x" bring them together and numbers together ;) so 3x+7x=222 4x=24 now divide both sides by 4 and you will have x=6 \[\frac{ 4x }{ 4 }=\frac{ 24 }{ 4 }\] so x= 6 ;)
 one year ago

ghaziBest ResponseYou've already chosen the best response.1
dw:1362525310743:dw clear?
 one year ago

LonelyandForgottenBest ResponseYou've already chosen the best response.1
wait.. how did you do that? :/
 one year ago

LonelyandForgottenBest ResponseYou've already chosen the best response.1
i think you are missing something
 one year ago

ghaziBest ResponseYou've already chosen the best response.1
nope i did , just bring 4x in the left so sign will be changed and take +2 on the right so sign will be changed and it will be +4x and on the right it will be 2 because sign gets interchanged
 one year ago

LonelyandForgottenBest ResponseYou've already chosen the best response.1
dw:1362525671903:dw
 one year ago

LonelyandForgottenBest ResponseYou've already chosen the best response.1
okay thank you :D your help is very much appriciated kinda Sir :D lol
 one year ago

LonelyandForgottenBest ResponseYou've already chosen the best response.1
wait.. kind * not kinda
 one year ago

LonelyandForgottenBest ResponseYou've already chosen the best response.1
haha sorry about that :D
 one year ago

ghaziBest ResponseYou've already chosen the best response.1
yea yea silly , post your questions please and lets do it ;)
 one year ago

LonelyandForgottenBest ResponseYou've already chosen the best response.1
next question?
 one year ago

LonelyandForgottenBest ResponseYou've already chosen the best response.1
okay post it lol
 one year ago

ghaziBest ResponseYou've already chosen the best response.1
well i am talking about your question lol not mine i have loads of question but i cant ask on this post of yours but yea if you wanna arrange another post i can draw and ask my questions and we can solve our questions if you like :D your maths and mine is kinda tough ;) ? what say? lets do it ;)
 one year ago

LonelyandForgottenBest ResponseYou've already chosen the best response.1
alright :) well thanks for your help, and everyone else too :P
 one year ago

ghaziBest ResponseYou've already chosen the best response.1
but i am sure you are smart enough
 one year ago
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