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Can someone teach me how to solve an equation with variables on both sides? i need help :(

Mathematics
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2x+3=4x-4 like this?
yeah something like that
put all that have x one side and that have not , to the other

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Other answers:

What is the equation you're trying to solve?
myko is right, but when you move a number to the other side of the eual sign you need to change the sign of the number itself. 4 becomes -4 and -4 becomes 4
well i understand that part but i cant go on further, i always get stuck :(
after you got something like this: ax=b do this: x=b/a andyou are done
so now how would you solve 4x=18?
|dw:1362524358288:dw| I dont know if this is right or wrong but i dont know where to go from there :/
that is the problem i am working on now
If you're getting the "X's" on one side then make sure you include the x. You're combining like terms. So it would be +3x under the -3x and the -7x. But you got it right so far after you get there your going to combine the +2 and the -22.
okay i can go on from there, thanks for your help :)
No problem.
|dw:1362525009117:dw| Is this right?
nope
ghazi :D
hi :D
:D BP hey ;)
can you help me please :(
BP i am :D
-3x + 2 = -7x-22 now bring like terms at one side so terms with variable lets say the ones with "x" bring them together and numbers together ;) so -3x+7x=-22-2 4x=-24 now divide both sides by 4 and you will have x=-6 \[\frac{ 4x }{ 4 }=\frac{ -24 }{ 4 }\] so x= -6 ;)
|dw:1362525310743:dw| clear?
wait.. how did you do that? :/
i think you are missing something
nope i did , just bring 4x in the left so sign will be changed and take +2 on the right so sign will be changed and it will be +4x and on the right it will be -2 because sign gets interchanged
|dw:1362525671903:dw|
lol
|dw:1362525692356:dw|
okay thank you :D your help is very much appriciated kinda Sir :D lol
haha :D
wait.. kind * not kinda
haha sorry about that :D
yea yea silly , post your questions please and lets do it ;)
next question?
of course yes
okay post it lol
:D
well i am talking about your question lol not mine i have loads of question but i cant ask on this post of yours but yea if you wanna arrange another post i can draw and ask my questions and we can solve our questions if you like :D your maths and mine is kinda tough ;) ? what say? lets do it ;)
alright :) well thanks for your help, and everyone else too :P
Goodbye!
but i am sure you are smart enough
see you soon ;)

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