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LonelyandForgotten Group Title

Can someone teach me how to solve an equation with variables on both sides? i need help :(

  • one year ago
  • one year ago

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  1. myko Group Title
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    2x+3=4x-4 like this?

    • one year ago
  2. LonelyandForgotten Group Title
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    yeah something like that

    • one year ago
  3. myko Group Title
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    put all that have x one side and that have not , to the other

    • one year ago
  4. hisgirl2012 Group Title
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    What is the equation you're trying to solve?

    • one year ago
  5. matineesuxxx Group Title
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    myko is right, but when you move a number to the other side of the eual sign you need to change the sign of the number itself. 4 becomes -4 and -4 becomes 4

    • one year ago
  6. LonelyandForgotten Group Title
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    well i understand that part but i cant go on further, i always get stuck :(

    • one year ago
  7. myko Group Title
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    after you got something like this: ax=b do this: x=b/a andyou are done

    • one year ago
  8. matineesuxxx Group Title
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    so now how would you solve 4x=18?

    • one year ago
  9. LonelyandForgotten Group Title
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    |dw:1362524358288:dw| I dont know if this is right or wrong but i dont know where to go from there :/

    • one year ago
  10. LonelyandForgotten Group Title
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    that is the problem i am working on now

    • one year ago
  11. hisgirl2012 Group Title
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    If you're getting the "X's" on one side then make sure you include the x. You're combining like terms. So it would be +3x under the -3x and the -7x. But you got it right so far after you get there your going to combine the +2 and the -22.

    • one year ago
  12. LonelyandForgotten Group Title
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    okay i can go on from there, thanks for your help :)

    • one year ago
  13. hisgirl2012 Group Title
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    No problem.

    • one year ago
  14. LonelyandForgotten Group Title
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    |dw:1362525009117:dw| Is this right?

    • one year ago
  15. ghazi Group Title
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    nope

    • one year ago
  16. LonelyandForgotten Group Title
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    ghazi :D

    • one year ago
  17. LonelyandForgotten Group Title
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    hi :D

    • one year ago
  18. ghazi Group Title
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    :D BP hey ;)

    • one year ago
  19. LonelyandForgotten Group Title
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    can you help me please :(

    • one year ago
  20. ghazi Group Title
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    BP i am :D

    • one year ago
  21. ghazi Group Title
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    -3x + 2 = -7x-22 now bring like terms at one side so terms with variable lets say the ones with "x" bring them together and numbers together ;) so -3x+7x=-22-2 4x=-24 now divide both sides by 4 and you will have x=-6 \[\frac{ 4x }{ 4 }=\frac{ -24 }{ 4 }\] so x= -6 ;)

    • one year ago
  22. ghazi Group Title
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    |dw:1362525310743:dw| clear?

    • one year ago
  23. LonelyandForgotten Group Title
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    wait.. how did you do that? :/

    • one year ago
  24. LonelyandForgotten Group Title
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    i think you are missing something

    • one year ago
  25. ghazi Group Title
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    nope i did , just bring 4x in the left so sign will be changed and take +2 on the right so sign will be changed and it will be +4x and on the right it will be -2 because sign gets interchanged

    • one year ago
  26. LonelyandForgotten Group Title
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    |dw:1362525671903:dw|

    • one year ago
  27. LonelyandForgotten Group Title
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    lol

    • one year ago
  28. ghazi Group Title
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    |dw:1362525692356:dw|

    • one year ago
  29. LonelyandForgotten Group Title
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    okay thank you :D your help is very much appriciated kinda Sir :D lol

    • one year ago
  30. LonelyandForgotten Group Title
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    haha :D

    • one year ago
  31. LonelyandForgotten Group Title
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    wait.. kind * not kinda

    • one year ago
  32. LonelyandForgotten Group Title
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    haha sorry about that :D

    • one year ago
  33. ghazi Group Title
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    yea yea silly , post your questions please and lets do it ;)

    • one year ago
  34. LonelyandForgotten Group Title
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    next question?

    • one year ago
  35. ghazi Group Title
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    of course yes

    • one year ago
  36. LonelyandForgotten Group Title
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    okay post it lol

    • one year ago
  37. LonelyandForgotten Group Title
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    :D

    • one year ago
  38. ghazi Group Title
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    well i am talking about your question lol not mine i have loads of question but i cant ask on this post of yours but yea if you wanna arrange another post i can draw and ask my questions and we can solve our questions if you like :D your maths and mine is kinda tough ;) ? what say? lets do it ;)

    • one year ago
  39. LonelyandForgotten Group Title
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    alright :) well thanks for your help, and everyone else too :P

    • one year ago
  40. LonelyandForgotten Group Title
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    Goodbye!

    • one year ago
  41. ghazi Group Title
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    but i am sure you are smart enough

    • one year ago
  42. ghazi Group Title
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    see you soon ;)

    • one year ago
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