Here's the question you clicked on:

55 members online
  • 0 replying
  • 0 viewing

overtonka

  • 3 years ago

Please help me learn how to do this... Simplify. Write answers with positive exponents. writing below

  • This Question is Closed
  1. overtonka
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    |dw:1362533750269:dw|

  2. saifoo.khan
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    \[\Large a^{-b} \to \frac{1}{a^b}\]Do you know about this property?

  3. overtonka
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    No no one has ever taught it to me

  4. saifoo.khan
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    So what i did was there was a negative exponent '-b'. So I flipped the fraction, making the -b to +b. Do you get it?

  5. overtonka
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    but how would you do it for this problem?

  6. saifoo.khan
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    Let's take c^-5 first. It have a negative exponent. so:\[\Large c^{-5} \to \frac{1}{c^5}\] We flipped the fraction. Making the exponent postive. Got it?

  7. overtonka
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    yeah so then we would have 1/c to the 5 power?

  8. Zuko
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    Essentially it looks like this: \[(\frac{ 1 }{ 3^2 })\times (\frac{ 1 }{ c ^{5} })\times (d ^{5})\] So therefore, in the end it will look like this: \[\frac{ d ^{4} }{ 9c ^{5} }\]

  9. Zuko
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    oops, in that first equation I wrote \[d ^{5}\]I meant \[d ^{4}\]

  10. Not the answer you are looking for?
    Search for more explanations.

    • Attachments:

Ask your own question

Sign Up
Find more explanations on OpenStudy
Privacy Policy