1. anonymous

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2. saifoo.khan

$\Large a^{-b} \to \frac{1}{a^b}$Do you know about this property?

3. anonymous

No no one has ever taught it to me

4. saifoo.khan

So what i did was there was a negative exponent '-b'. So I flipped the fraction, making the -b to +b. Do you get it?

5. anonymous

but how would you do it for this problem?

6. saifoo.khan

Let's take c^-5 first. It have a negative exponent. so:$\Large c^{-5} \to \frac{1}{c^5}$ We flipped the fraction. Making the exponent postive. Got it?

7. anonymous

yeah so then we would have 1/c to the 5 power?

8. anonymous

Essentially it looks like this: $(\frac{ 1 }{ 3^2 })\times (\frac{ 1 }{ c ^{5} })\times (d ^{5})$ So therefore, in the end it will look like this: $\frac{ d ^{4} }{ 9c ^{5} }$

9. anonymous

oops, in that first equation I wrote $d ^{5}$I meant $d ^{4}$