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Grazes

  • 3 years ago

Where 0<=x<360, Solve the equation

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  1. Grazes
    • 3 years ago
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    \[3\sin x-5+\csc x=0\]

  2. Mertsj
    • 3 years ago
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    \[3\sin ^2x-5\sin x+1=0\]

  3. Grazes
    • 3 years ago
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    But I simplified that to \[\sin ^{2}x-3\sin x+1\]

  4. Mertsj
    • 3 years ago
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    I don't see how you get that?

  5. Grazes
    • 3 years ago
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    Give me a sec

  6. Grazes
    • 3 years ago
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    Oh wait.. I was looking at something else. My bad.

  7. Grazes
    • 3 years ago
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    Would I use the quadratic formula to find the roots of 3sin^2x−5sinx+1=0?

  8. Mertsj
    • 3 years ago
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    \[3sinx \times sinx-5\times sinx+\frac{1}{sinx}\times sinx=0 \times sinx\]

  9. Mertsj
    • 3 years ago
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    yes

  10. Grazes
    • 3 years ago
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    \[\frac{ 3\pm \sqrt{5}}{ 2 }\] But then what? I can't isolate for x, can I?

  11. Mertsj
    • 3 years ago
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    sin x = (3+sqrt5)/2 or sin x = (3-sqrt5)/2

  12. Grazes
    • 3 years ago
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    So would I find the arcsin of (3+sqrt5)/2 and (3-sqrt5)/2 for x?

  13. Mertsj
    • 3 years ago
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    Can't be the first one because sin can't be bigger than 1.

  14. Mertsj
    • 3 years ago
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    so sin x = .3820

  15. Grazes
    • 3 years ago
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    Does there happen to be a way I could solve this without using a calculator?

  16. Mertsj
    • 3 years ago
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    If you have a table of values you could.

  17. Mertsj
    • 3 years ago
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    Did you get 22.5 degrees and 157.5 degrees?

  18. genius12
    • 3 years ago
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    Do we need my assistance here or are we ok?

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