A community for students. Sign up today!
Here's the question you clicked on:
 0 viewing

This Question is Closed

experimentX
 one year ago
Best ResponseYou've already chosen the best response.0dw:1362585994965:dw

experimentX
 one year ago
Best ResponseYou've already chosen the best response.0dw:1362586038538:dw

experimentX
 one year ago
Best ResponseYou've already chosen the best response.0dw:1362586072732:dw \[ \cos \theta = \frac{<u, v>}{u\; v}\]

experimentX
 one year ago
Best ResponseYou've already chosen the best response.0so you have the component of u along v is \[ \large \frac{u\;v}{v} \times \frac{<u, v>}{u\; v}= \frac{v <u,v>}{v^2} = \frac{v <u,v>}{<v,v>}\]

experimentX
 one year ago
Best ResponseYou've already chosen the best response.0using vector law of addition we get .. the component perpendicular to V is \[V  \frac{V <U,V>}{<V,V>} \]

experimentX
 one year ago
Best ResponseYou've already chosen the best response.0dw:1362586404101:dw

experimentX
 one year ago
Best ResponseYou've already chosen the best response.0dw:1362586480133:dw

experimentX
 one year ago
Best ResponseYou've already chosen the best response.0dw:1362586557753:dw you can check for dot product ... and show be able to verify which should be perpendicular to which and ...same goes for parallel.

Callisto
 one year ago
Best ResponseYou've already chosen the best response.1dw:1362586938881:dw

experimentX
 one year ago
Best ResponseYou've already chosen the best response.0dw:1362587300516:dw

Callisto
 one year ago
Best ResponseYou've already chosen the best response.1Once we find u along v, we can express u as a linear combination of v and v⊥?!

experimentX
 one year ago
Best ResponseYou've already chosen the best response.0yes .. .lol, that will be equal to u

experimentX
 one year ago
Best ResponseYou've already chosen the best response.0use brackets to separate it ... and don't do arithmetic.
Ask your own question
Ask a QuestionFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.