## experimentX Group Title Q: one year ago one year ago

1. experimentX Group Title

|dw:1362585994965:dw|

2. experimentX Group Title

|dw:1362586038538:dw|

3. experimentX Group Title

|dw:1362586072732:dw| $\cos \theta = \frac{<u, v>}{||u||\; ||v||}$

4. experimentX Group Title

so you have the component of u along v is $\large \frac{||u||\;v}{||v||} \times \frac{<u, v>}{||u||\; ||v||}= \frac{v <u,v>}{||v||^2} = \frac{v <u,v>}{<v,v>}$

5. experimentX Group Title

using vector law of addition we get .. the component perpendicular to V is $V - \frac{V <U,V>}{<V,V>}$

6. experimentX Group Title

|dw:1362586404101:dw|

7. experimentX Group Title

|dw:1362586480133:dw|

8. experimentX Group Title

|dw:1362586557753:dw| you can check for dot product ... and show be able to verify which should be perpendicular to which and ...same goes for parallel.

9. Callisto Group Title

|dw:1362586938881:dw|

10. experimentX Group Title

|dw:1362587300516:dw|

11. Callisto Group Title

Once we find u along v, we can express u as a linear combination of v and v⊥?!

12. experimentX Group Title

yes .. .lol, that will be equal to u

13. experimentX Group Title

use brackets to separate it ... and don't do arithmetic.