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Q:

MIT 18.01 Single Variable Calculus (OCW)
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|dw:1362585994965:dw|
|dw:1362586038538:dw|
|dw:1362586072732:dw| \[ \cos \theta = \frac{}{||u||\; ||v||}\]

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Other answers:

so you have the component of u along v is \[ \large \frac{||u||\;v}{||v||} \times \frac{}{||u||\; ||v||}= \frac{v }{||v||^2} = \frac{v }{}\]
using vector law of addition we get .. the component perpendicular to V is \[V - \frac{V }{} \]
|dw:1362586404101:dw|
|dw:1362586480133:dw|
|dw:1362586557753:dw| you can check for dot product ... and show be able to verify which should be perpendicular to which and ...same goes for parallel.
|dw:1362586938881:dw|
|dw:1362587300516:dw|
Once we find u along v, we can express u as a linear combination of v and v⊥?!
yes .. .lol, that will be equal to u
use brackets to separate it ... and don't do arithmetic.

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