## experimentX 3 years ago Q:

1. experimentX

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2. experimentX

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3. experimentX

|dw:1362586072732:dw| $\cos \theta = \frac{<u, v>}{||u||\; ||v||}$

4. experimentX

so you have the component of u along v is $\large \frac{||u||\;v}{||v||} \times \frac{<u, v>}{||u||\; ||v||}= \frac{v <u,v>}{||v||^2} = \frac{v <u,v>}{<v,v>}$

5. experimentX

using vector law of addition we get .. the component perpendicular to V is $V - \frac{V <U,V>}{<V,V>}$

6. experimentX

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7. experimentX

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8. experimentX

|dw:1362586557753:dw| you can check for dot product ... and show be able to verify which should be perpendicular to which and ...same goes for parallel.

9. Callisto

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10. experimentX

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11. Callisto

Once we find u along v, we can express u as a linear combination of v and v⊥?!

12. experimentX

yes .. .lol, that will be equal to u

13. experimentX

use brackets to separate it ... and don't do arithmetic.